This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>
using namespace std;
using namespace __gnu_pbds;
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;
typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;
typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;
template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;
#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)
#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()
const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 100001;
int N, A[2001];
ll dp[2001][2001];
int main() {
ios_base::sync_with_stdio(0); cin.tie(0);
cin >> N;
FOR(i,1,N+1) cin >> A[i];
F0R(i,N+1) FOR(j,1,N+1) dp[i][j] = -INF;
FOR(i,1,N+1) FOR(j,1,N+1) dp[i][j] = max(dp[i-1][j],(i>1?dp[i-2][j-1]+A[i]:dp[i-1][j-1]+A[i]));
// cout << dp[3][2] << " " << dp[1][1] << "\n";
FOR(j,1,(N+1)/2+1) {
ll ans = 0;
// FOR(i,1,N+1) cout << dp[i][j] << " ";
FOR(i,1,N+1) ans = max(ans,dp[i][j]);
cout << ans << "\n";
}
}
/* Look for:
* the exact constraints (multiple sets are too slow for n=10^6 :( )
* special cases (n=1?)
* overflow (ll vs int?)
* array bounds
*/
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