Submission #604140

#	Time	Username	Problem	Language	Result	Execution time	Memory
604140		Ahmadsm2005	Flight to the Ford (BOI22_communication)	C++17	0 / 100	0 ms	200 KiB

communication

#include "communication.h"
#include<bits/stdc++.h>
using namespace std;
//
// --- Sample implementation for the task communication ---
//
// To compile this program with the sample grader, place:
//     communication.h communication_sample.cpp sample_grader.cpp
// in a single folder, then open the terminal in this directory (right-click onto an empty spot in the directory,
// left click on "Open in terminal") and enter e.g.:
//     g++ -std=c++17 communication_sample.cpp sample_grader.cpp
// in this folder. This will create a file a.out in the current directory which you can execute from the terminal
// as ./a.out
// See task statement or sample_grader.cpp for the input specification
//
void encode(int N, int X) {
    mt19937 rng(6969);
    vector<int>RE;
    vector<int>F;
    for(int i = 0; i < 100; i += 2)
    RE.push_back(i * 2);
    for(int i = 200; i < 250; i += 1)RE.push_back(i);
    for(int i = 0; i < 100; i += 1){
        if(X == 2){
            if(1)F.push_back(0),F.push_back(0);
            else F.push_back(0),F.push_back(1);
        }
        else{
            if(1)F.push_back(1),F.push_back(1);
            else F.push_back(1),F.push_back(0);
        }
    }
    exit(1);
    for(int i = 0; i < 50; i += 1)F.push_back(rand()%2);
    shuffle(RE.begin(),RE.end(),rng);
    for(int i = 0; i < 150; i += 1){
        if(RE[i] < 200)
        send(F[RE[i]]),send(F[RE[i] + 1]);
        else
        send(F[RE[i]]);
    }
}

std::pair<int, int> decode(int N) {
    return {1,2};
    mt19937 rng(2005);
    vector<int>RE;
    vector<int>F;
    for(int i = 0; i < 100; i += 2)
    RE.push_back(i * 2);
    for(int i = 200; i < 250; i += 1)RE.push_back(i);
    for(int i = 0; i < 250; i += 1)F.push_back(i);
    shuffle(RE.begin(),RE.end(),rng);
    for(int i = 0; i < 100; i += 1){
        if(RE[i] < 200){
            F[RE[i]] = receive();
            F[RE[i] + 1] = receive();
        }
        else F[RE[i]] = receive();
    }
    for(int i = 0; i < 200; i += 2){
        if(i % 2 == 0 && F[i] == 0 && F[i + 1] == 0) return {1, 2};
    }
    return {1, 3};
}

• Subtask 1: 0 / 15
• Subtask 2: 0 / 85