Submission #603263

#TimeUsernameProblemLanguageResultExecution timeMemory
603263arayiBank (IZhO14_bank)C++17
71 / 100
401 ms262144 KiB
// Arayi #include <bits/stdc++.h> #define fr first #define sc second #define MP make_pair #define ad push_back #define PB push_back #define fastio \ ios_base::sync_with_stdio(false); \ cin.tie(0); \ cout.tie(0); #define lli long long int #define y1 arayikhalatyan #define j1 jigglypuff #define ld long double #define itn int #define pir pair<int, int> #define all(x) (x).begin(), (x).end() #define str string #define enl endl #define en endl #define cd complex<long double> #define vcd vector<cd> #define vii vector<int> #define vlli vector<lli> using namespace std; lli gcd(lli a, lli b) { return (b == 0LL ? a : gcd(b, a % b)); } ld dist(ld x, ld y1, ld x2, ld y2) { return sqrt((x - x2) * (x - x2) + (y1 - y2) * (y1 - y2)); } lli S(lli a) { return (a * (a + 1LL)) / 2; } mt19937 rnd(363542); char vow[] = {'a', 'e', 'i', 'o', 'u'}; int dx[] = {0, -1, 0, 1, -1, -1, 1, 1, 0}; int dy[] = {-1, 0, 1, 0, -1, 1, -1, 1, 0}; char dc[] = {'R', 'D', 'L', 'U'}; const int N = 3e6 + 20; const lli mod = LLONG_MAX; const ld pi = acos(-1); const ld e = 1e-13; const int T = 200; lli bp(lli a, lli b = mod - 2LL) { lli ret = 1; while (b) { if (b & 1) ret *= a, ret %= mod; a *= a; a %= mod; b >>= 1; } return ret; } ostream &operator<<(ostream &c, pir a) { c << a.fr << " " << a.sc; return c; } template <class T> void maxi(T &a, T b) { a = max(a, b); } template <class T> void mini(T &a, T b) { a = min(a, b); } int n, m; int a[N], b[N]; vii fp[N]; bool dp[21][N]; vii s[N]; int main() { fastio; cin >> n >> m; for (int i = 0; i < n; i++) cin >> a[i]; for (int i = 0; i < m; i++) cin >> b[i]; for (int x = 0; x < (1 << m); x++) { int sum = 0; for (int i = 0; i < m; i++) if ((1 << i) & x) sum += b[i]; fp[sum].ad(x); } dp[0][0] = 1; int sum = 0; for (int i = 0; i < n; i++) { sum += a[i]; for (int j = 0; j < (1 << m); j++) s[j].clear(); for(auto p : fp[a[i]]) s[p].ad(p); for (int j = 0; j < m; j++) { for (int x = (1 << m) - 1; x >= 0; x--) { if (((1 << j) & x)) continue; for (auto p : s[x]) s[x ^ (1 << j)].ad(p); } } for (auto p : fp[sum]) { for (auto p1 : s[p]) { if (dp[i][p ^ p1]) { dp[i + 1][p] = 1; break; } } } } bool pat = 0; for (auto p : fp[sum]) if (dp[n][p]) pat = 1; if (pat) cout << "YES" << endl; else cout << "NO" << endl; return 0; } /* __ *(><)* \/ / ||/ --|| || /\ / \ / \ */
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