Submission #603194

#	Time	Username	Problem	Language	Result	Execution time	Memory
603194		definitelynotmee	Rectangles (IOI19_rect)	C++17	13 / 100	611 ms	208468 KiB

rect

#include "rect.h"
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using pii = pair<int,int>;
using pll = pair<ll,ll>;
template<typename T> using matrix = vector<vector<T>>;
#define ff first
#define ss second
#define all(x) x.begin(), x.end()

struct cebola{
    int pai, minx, maxx, miny, maxy, sz;
};

long long count_rectangles(std::vector<std::vector<int> > a) {
	
    int n = a.size(), m = a[0].size();
    int tot = n*m;

    vector<cebola> v(tot);

    for(int i = 0; i < tot; i++){
        v[i] = {i,i%m,i%m,i/m,i/m,1};
    }
    auto find =[&](int id, auto find){
        if(v[id].pai == id)
            return id;
        return v[id].pai = find(v[id].pai,find);
    };

    auto onion =[&](int a, int b){
        a= find(a,find);
        b = find(b,find);
        if(a == b)
            return;
        v[a].pai = b;
        v[b].minx = min(v[b].minx,v[a].minx);
        v[b].miny = min(v[b].miny,v[a].miny);
        v[b].maxx = max(v[b].maxx,v[a].maxx);
        v[b].maxy = max(v[b].maxy,v[a].maxy);
        v[b].sz+=v[a].sz;
    };

    int dx[]{1,0,-1,0}, dy[]{0,1,0,-1};
    for(int i = 0; i < tot; i++){
        int x = i%m, y = i/m;
        for(int j = 0; j < 4; j++){
            int xi = x + dx[j], yi = y+ dy[j];
            if(xi < 0 || xi >= m || yi < 0 || yi >= n){
                continue;
            }
            int id = yi*m+xi;
            // cout << dx[j] << ' ' << dy[j] << '\n';
            // cout << "->" << i << ' '<< x << ' ' << y << " <=> " << id << ' ' <<xi << ' ' << yi << '\n';
            if(a[y][x] == 0 && a[yi][xi] == 0)
                onion(i,id) ;
        }
    }
    int resp = 0;

    for(int i = 0; i < tot; i++){
        int x = i%m, y = i/m;
        if(a[y][x] != 0 || v[i].pai != i)
            continue;
        // cout << x << ' ' << y << '\n';
        // cout << v[i].minx << ' ' << v[i].maxx << ' ' << v[i].miny << ' ' << v[i].maxy << '\n';
        if(v[i].maxx == m-1 || v[i].minx == 0 || v[i].miny == 0 || v[i].maxy == n-1)
            continue;
        //cout << x << ' ' << y << '\n';
        if((v[i].maxx-v[i].minx+1)*(v[i].maxy-v[i].miny+1) == v[i].sz)
            resp++;
    }

    return resp;
}

• Subtask 1: 0 / 8
• Subtask 2: 0 / 7
• Subtask 3: 0 / 12
• Subtask 4: 0 / 22
• Subtask 5: 0 / 10
• Subtask 6: 13 / 13
• Subtask 7: 0 / 28