Submission #601955

#	Time	Username	Problem	Language	Result	Execution time	Memory
601955		OttoTheDino	Mixture (BOI20_mixture)	C++17	30 / 100	2 ms	340 KiB

Mixture

#include <bits/stdc++.h>
using namespace std;

#define rep(i,s,e)                  for (int i = s; i <= e; ++i)
#define rrep(i,s,e)                 for (int i = s; i >= e; --i)
#define pb                          push_back
#define pf                          push_front
#define fi                          first
#define se                          second
#define all(a)                      a.begin(), a.end()
#define len(a)                      (int)a.size()
typedef long long ll;
typedef pair<int, int> ii;
typedef pair<ll, ll> pll;
typedef vector<ii> vii;
typedef vector<int> vi;
typedef vector<double> vd;
typedef vector<string> vs;
typedef vector<ll> vll;

const double eps = 1e-6, pi = acos(-1);
const int mx = 1e5;

bool eq (double a, double b) {
    return abs(a-b)<=2*eps;
}

double ang[mx+1] = {};
int bud[mx+1] = {}, b = 0;
set<pair<double,int>> st2;

void do_two (int id) {
    double poss[5] = {fmod(ang[id]+pi+eps,2*pi),
                        ang[id]+pi-eps,
                        fmod(ang[id]+pi-eps,2*pi),
                        fmod(ang[id]+pi,2*pi)+eps,
                        fmod(ang[id]+pi,2*pi)-eps};
    rep (i,0,4) {
        double pos = poss[i];
        auto it = st2.lower_bound({pos, 0});
        if (it!=st2.end() && eq((*it).fi,pos)) {
            bud[id] = (*it).se;
            bud[(*it).se] = id;
            st2.erase(it);
            b++;
            return;
        }
    }

    st2.insert({ang[id], id});
}

int main() {
    ios::sync_with_stdio(0);
    cin.tie(0);

    double S, P, G; cin >> S >> P >> G;

    double X = S/(S+P+G), Y = P/(S+P+G);

    int n; cin >>n;

    int id = 1, a=0, p[n+1] = {};
    multiset<double> st3; 

    rep (i,1,n) {
        char tp; cin >> tp;
        if (tp=='A') {
            double Si, Pi, Gi;
            cin >> Si >> Pi >> Gi;
            double x = Si/(Si+Pi+Gi), y = Pi/(Si+Pi+Gi);
            if (eq(X,x) && eq(Y,y)) {
                a++;
                p[id] = 1;
            }
            else {
                ang[id] = fmod(pi+atan2(y-Y, x-X),2*pi);
//                cout << "ang #" << id << ": " << ang[id] << endl;
                st3.insert(ang[id]);
                do_two(id);
            }
            ++id;
        }
        else {
            int x; cin >> x;
            if (p[x])
                a--;
            else {
                st3.erase(st3.find(ang[x]));
                if (st2.find({ang[x],x})!=st2.end()) st2.erase({ang[x],x});
                if (bud[x]) {
                    b--;
                    bud[bud[x]] = 0;
                    do_two(bud[x]);
                    bud[x] = 0;
                }
            }
        }
        //cout << i << " " << b << endl;

        bool c = 0;
        if (len(st3)>2) {
            double un = (*st3.begin());
            double dos = (*--st3.upper_bound(un+pi));
            double tres = (*--st3.upper_bound(dos+pi));
            if (max(dos-un,max(tres-dos,2*pi+un-tres))<=pi) c = 1; 
        }


        if (a) cout << "1\n";
        else if (b) cout << "2\n";
        else if (c) cout << "3\n";
        else cout << "0\n";
    }

    return 0;
}

• Subtask 1: 13 / 13
• Subtask 2: 17 / 17
• Subtask 3: 0 / 30
• Subtask 4: 0 / 40