Submission #601218

#TimeUsernameProblemLanguageResultExecution timeMemory
601218maomao90The Xana coup (BOI21_xanadu)C++17
100 / 100
80 ms16560 KiB
// Hallelujah, praise the one who set me free // Hallelujah, death has lost its grip on me // You have broken every chain, There's salvation in your name // Jesus Christ, my living hope #include <bits/stdc++.h> using namespace std; #define REP(i, s, e) for (int i = (s); i < (e); i++) #define RREP(i, s, e) for (int i = (s); i >= (e); i--) template <class T> inline bool mnto(T& a, T b) {return a > b ? a = b, 1 : 0;} template <class T> inline bool mxto(T& a, T b) {return a < b ? a = b, 1: 0;} typedef long long ll; typedef long double ld; #define FI first #define SE second typedef pair<int, int> ii; typedef pair<ll, ll> pll; typedef tuple<int, int, int> iii; #define ALL(_a) _a.begin(), _a.end() #define SZ(_a) (int) _a.size() #define pb push_back typedef vector<int> vi; typedef vector<ll> vll; typedef vector<ii> vii; typedef vector<iii> viii; #ifndef DEBUG #define cerr if (0) cerr #endif const int INF = 1000000005; const ll LINF = 1000000000000000005ll; const int MAXN = 100005; int n; vi adj[MAXN]; bool a[MAXN]; int dp[MAXN][2][2]; void dfs(int u, int p) { bool rt = 1; for (int v : adj[u]) { if (v == p) { continue; } rt = 0; dfs(v, u); } if (rt) { REP (x, 0, 2) { REP (y, 0, 2) { dp[u][x][y] = INF; } } REP (x, 0, 2) { dp[u][x][a[u] ^ x] = x; } return; } REP (x, 0, 2) { // x = whether self is pressed int y = a[u] ^ x; int sm = x; for (int v : adj[u]) { if (v == p) { continue; } if (dp[v][0][x] < dp[v][1][x]) { sm += dp[v][0][x]; mnto(sm, INF); } else { sm += dp[v][1][x]; mnto(sm, INF); y ^= 1; } } dp[u][x][y] = sm; int mn = INF; for (int v : adj[u]) { if (v == p) { continue; } mnto(mn, abs(dp[v][0][x] - dp[v][1][x])); } dp[u][x][y ^ 1] = min(sm + mn, INF); } } int main() { #ifndef DEBUG ios::sync_with_stdio(0), cin.tie(0); #endif cin >> n; REP (i, 1, n) { int u, v; cin >> u >> v; adj[u].pb(v); adj[v].pb(u); } REP (i, 1, n + 1) { cin >> a[i]; } dfs(1, -1); int ans = INF; REP (x, 0, 2) { mnto(ans, dp[1][x][0]); } if (ans == INF) { cout << "impossible\n"; } else { cout << ans << '\n'; } return 0; }
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