Submission #599209

#	Time	Username	Problem	Language	Result	Execution time	Memory
599209		isaachew	Global Warming (CEOI18_glo)	C++17	10 / 100	126 ms	3872 KiB

glo

#include <bits/stdc++.h>
/*
 A suffix as the interval is not optimal
 
 ST3: Calc LIS and range for every interval by getting longest LIS for ending
 
 LIS with std::map tracking
 
 ST4 (LIS): calculate the LIS normally with std::map; O(n log n)
 ST5: calculate LIS but 3 states based on whether in interval or not; O(nxlog n)
 ST6: arbitrary distance
 
 Change one number at a time; this will change
 
 
 
 Only two transition differences can be affected by the shift
 */
int n,x;
int main(){
    std::cin>>n>>x;
    std::vector<int> vec;
    for(int i=0;i<n;i++){
        int t;
        std::cin>>t;
        vec.push_back(t);
    }
    if(x==0){
        std::vector<int> swlis(n+1,1000000001);
        int lis=0;
        for(int i=0;i<n;i++){
            int slis=std::lower_bound(swlis.begin(),swlis.end(),vec[i])-swlis.begin();//first slot not less than
            //std::cout<<slis<<'\n';
            lis=std::max(lis,slis);
            swlis[slis]=vec[i];
        }
        std::cout<<lis+1<<'\n';
        return 0;
    }
    //*
    if(n*x<2000000){
        int lis=0;
        for(int l=-x;l<=x;l++){
            std::vector<std::vector<int>> vals(3,std::vector<int>(n,0));
            std::vector<std::vector<int>> rlis(3,std::vector<int>(n+1,2000000000));//minimum value with a LIS of (number) (or less?)
            for(int i=0;i<n;i++){
                int cur=vec[i];
                int lb=std::lower_bound(rlis[0].begin(),rlis[0].end(),cur)-rlis[0].begin();
                
                int lb2_1=std::lower_bound(rlis[0].begin(),rlis[0].end(),cur+l)-rlis[0].begin();
                int lb2_2=std::lower_bound(rlis[1].begin(),rlis[1].end(),cur)-rlis[1].begin();
                
                int lb3_1=std::lower_bound(rlis[1].begin(),rlis[1].end(),cur-l)-rlis[1].begin();
                int lb3_2=std::lower_bound(rlis[2].begin(),rlis[2].end(),cur)-rlis[2].begin();
                
                vals[0][i]=lb;
                rlis[0][vals[0][i]]=cur;
                vals[1][i]=std::max(lb2_1,lb2_2);
                rlis[1][vals[1][i]]=cur;
                vals[2][i]=std::max(lb3_1,lb3_2);
                rlis[2][vals[2][i]]=cur;
                
                lis=std::max(lis,vals[0][i]);
                lis=std::max(lis,vals[1][i]);
                lis=std::max(lis,vals[2][i]);
            }
        }
        std::cout<<lis+1<<'\n';
    }
     //*/
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 10
• Subtask 3: 0 / 13
• Subtask 4: 10 / 10
• Subtask 5: 0 / 20
• Subtask 6: 0 / 17
• Subtask 7: 0 / 25