Submission #598523

#	Time	Username	Problem	Language	Result	Execution time	Memory
598523		cheissmart	Unscrambling a Messy Bug (IOI16_messy)	C++14	0 / 100	2 ms	468 KiB

messy

#include "messy.h"
#include <bits/stdc++.h>
#define IO_OP std::ios::sync_with_stdio(0); std::cin.tie(0);
#define F first
#define S second
#define V vector
#define PB push_back
#define EB emplace_back
#define MP make_pair
#define SZ(v) int((v).size())
#define ALL(v) (v).begin(), (v).end()

using namespace std;

typedef long long ll;
typedef pair<int, int> pi;
typedef V<int> vi;

const int INF = 1e9 + 7;

vi restore_permutation(int n, int w, int r) {
    {
        function<void(int, int, string)> dfs = [&] (int l, int r, string s) {
            if(r - l == 1) return;
            int m = (l + r) / 2;
            for(int i = l; i < m; i++) {
                string t = s;
                t[i] = '1';
                add_element(t);
            }
            {
                string t = s;
                for(int i = m; i < r; i++)
                    t[i] = '1';
                dfs(l, m, t);
            }
            {
                string t = s;
                for(int i = l; i < m; i++)
                    t[i] = '1';
                dfs(m, r, t);
            }
        }; 
        dfs(0, n, string(n, '0'));
    }
    compile_set();
    vi ans(n);
    {
        function<void(int, int, string, vi)> dfs = [&] (int l, int r, string s, vi x) {
            assert(SZ(x) == r - l);
            if(r - l == 1) {
                ans[x[0]] = l;
                return;
            }
            int m = (r + l) / 2;
            vi left, right;
            for(int i:x) {
                string t = s;
                t[i] = '1';
                if(check_element(t)) {
                    left.PB(i);
                } else {
                    right.PB(i);
                }
            }
            cout << SZ(left) << " " << SZ(right) << endl;
            {
                string t = s;
                for(int i:right)
                    t[i] = '1';
                dfs(l, m, t, left);
            }
            {
                string t = s;
                for(int i:left)
                    t[i] = '1';
                dfs(m, r, t, right);
            }
        };
        vi tt;
        for(int i = 0; i < n; i++) tt.PB(i);
        dfs(0, n, string(n, '0'), tt);
    }
    return ans;

}

• Subtask 1: 0 / 20
• Subtask 2: 0 / 18
• Subtask 3: 0 / 11
• Subtask 4: 0 / 21
• Subtask 5: 0 / 30