Submission #59370

#TimeUsernameProblemLanguageResultExecution timeMemory
59370Benqtimeismoney (balkan11_timeismoney)C++14
100 / 100
450 ms1000 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/tree_policy.hpp> #include <ext/pb_ds/assoc_container.hpp> using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef long double ld; typedef complex<ld> cd; typedef pair<int, int> pi; typedef pair<ll,ll> pl; typedef pair<ld,ld> pd; typedef vector<int> vi; typedef vector<ld> vd; typedef vector<ll> vl; typedef vector<pi> vpi; typedef vector<pl> vpl; typedef vector<cd> vcd; template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; #define FOR(i, a, b) for (int i=a; i<(b); i++) #define F0R(i, a) for (int i=0; i<(a); i++) #define FORd(i,a,b) for (int i = (b)-1; i >= a; i--) #define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--) #define sz(x) (int)(x).size() #define mp make_pair #define pb push_back #define f first #define s second #define lb lower_bound #define ub upper_bound #define all(x) x.begin(), x.end() const int MOD = 1000000007; const ll INF = 1e18; const int MX = 100001; int N,M,r1,r2; vector<array<int,4>> ed; bool cmp(array<int,4> x, array<int,4> y) { return r1*x[2]+r2*x[3] < r1*y[2]+r2*y[3]; } template<int SZ> struct DSU { int par[SZ], sz[SZ]; DSU() { F0R(i,SZ) par[i] = i, sz[i] = 1; } int get(int x) { // path compression if (par[x] != x) par[x] = get(par[x]); return par[x]; } bool unite(int x, int y) { // union-by-rank x = get(x), y = get(y); if (x == y) return 0; if (sz[x] < sz[y]) swap(x,y); sz[x] += sz[y], par[y] = x; return 1; } }; vpi tmp; pair<pl,vpi> ans = {{MOD,MOD},{}}; pl kruskal() { tmp.clear(); DSU<201> D; sort(all(ed),cmp); ll x = 0, y = 0; for (auto a: ed) if (D.unite(a[0],a[1])) { tmp.pb({a[0],a[1]}); x += a[2], y += a[3]; } return {x,y}; } int main() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> N >> M; F0R(i,M) { int x,y,t,c; cin >> x >> y >> t >> c; ed.pb({x,y,t,c}); } F0R(i,257) { r1 = i, r2 = 256; pl z = kruskal(); if (z.f*z.s < ans.f.f*ans.f.s) ans = {z,tmp}; } F0R(i,257) { r1 = 256, r2 = i; pl z = kruskal(); if (z.f*z.s < ans.f.f*ans.f.s) ans = {z,tmp}; } cout << ans.f.f << " " << ans.f.s << "\n"; for (auto a: ans.s) cout << a.f << " " << a.s << "\n"; } /* Look for: * the exact constraints (multiple sets are too slow for n=10^6 :( ) * special cases (n=1?) * overflow (ll vs int?) * array bounds */
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