Submission #59343

#TimeUsernameProblemLanguageResultExecution timeMemory
59343BenqUzastopni (COCI15_uzastopni)C++14
104 / 160
243 ms33792 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/tree_policy.hpp> #include <ext/pb_ds/assoc_container.hpp> using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef long double ld; typedef complex<ld> cd; typedef pair<int, int> pi; typedef pair<ll,ll> pl; typedef pair<ld,ld> pd; typedef vector<int> vi; typedef vector<ld> vd; typedef vector<ll> vl; typedef vector<pi> vpi; typedef vector<pl> vpl; typedef vector<cd> vcd; template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; #define FOR(i, a, b) for (int i=a; i<(b); i++) #define F0R(i, a) for (int i=0; i<(a); i++) #define FORd(i,a,b) for (int i = (b)-1; i >= a; i--) #define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--) #define sz(x) (int)(x).size() #define mp make_pair #define pb push_back #define f first #define s second #define lb lower_bound #define ub upper_bound #define all(x) x.begin(), x.end() const int MOD = 1000000007; const ll INF = 1e18; const int MX = 10001; int N, V[MX]; vi child[MX]; bitset<101> lo[MX], hi[MX]; void solve(int x) { vi oklo[101], okhi[101]; lo[x][V[x]] = hi[x][V[x]] = 1; for (int i: child[x]) { solve(i); FOR(a,1,101) if (lo[i][a]) FOR(b,1,101) if (hi[i][b]) { if (V[x] < a) okhi[a].pb(b); if (b < V[x]) oklo[b].pb(a); } } FORd(i,2,V[x]+1) if (lo[x][i]) for (int t: oklo[i-1]) lo[x][t] = 1; FOR(i,V[x],100) if (hi[x][i]) for (int t: okhi[i+1]) hi[x][t] = 1; } int main() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> N; FOR(i,1,N+1) cin >> V[i]; F0R(i,N-1) { int a,b; cin >> a >> b; child[a].pb(b); } solve(1); cout << lo[1].count()*hi[1].count(); } /* Look for: * the exact constraints (multiple sets are too slow for n=10^6 :( ) * special cases (n=1?) * overflow (ll vs int?) * array bounds */
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