Submission #592728

#TimeUsernameProblemLanguageResultExecution timeMemory
592728l_rehoTeams (IOI15_teams)C++14
0 / 100
4062 ms8924 KiB


#include <bits/stdc++.h>
using namespace std;

vector<pair<int, int>> ranges;
int n;

bool compare(pair<int, int> p1, pair<int, int> p2){
	return (p1.second < p2.second) || ((p1.second == p2.second && p1.first < p2.first));
}

void init(int N, int A[], int B[]) {
	n = N;
	
	for(int i = 0; i < N; i++) ranges.push_back({A[i], B[i]}); 
	sort(ranges.begin(), ranges.end(), compare);

}

int can(int M, int K[]) {
	
	vector<bool> assigned(n, false);
	
	sort(K, K+M);
	
		
	int init = 0;
	
	for(int i = 0; i < M; i++){
		
		int cnt = 0;
		bool ok = false;
		// naive O(N)
		
		// posso contare il numero di studenti che vanno bene tramite una binary search
		// però poi come li marchio assegnati?
		
		for(int j = init; j < n; j++){
		
			int start = ranges[j].first;
			int end = ranges[j].second;
			
			if(start <= K[i] && end >= K[i] && !assigned[j]) cnt++, assigned[j] = true;
			
			if(cnt == K[i]){ok = true; init=j+1; break;}
			
		}
		// logn O(logN)
		
		// contare il numero di intervalli che contengono un'altro intervallo
		
		// A = cnt({K[i], K[i+1]})
		// B = cnt({K[i+1], K[i+1]}) B - A se A <= K[i], altrimenti tolgo K[i]
		
		if(!ok) return 0;
	}
	
	
	return 1;
}
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