이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef long double ld;
#include "nice_lines.h"
map<ll, map<ll, ld> > cache;
ld Q(ll x, ll y){
	if (cache[x].count(y)) return cache[x][y];
	else return cache[x][y] = query((ld)x, (ld)y);
}
ld getdiff(ll x, ll y){
	return Q(x, y+1) - Q(x, y);
}
vector<ll> ans;
vector<ld> diffs;
ll X = 20001;
void dnc(ll L, ll R, ld S, ld E){
	if (abs(S-E) < 1e-5){
		return;
	}
	///printf("DNC %lld %lld %.20Lf %.20Lf, %.20Lf\n",L,R,S,E, E-S);
	if (L >= R) return;
	for (auto x : diffs){
		if (abs(E-S-x) < 3e-11){
			///printf("FOUND %.20Lf %.20Lf = %.20Lf\n",S,E,E-S-x);
			long double difff = Q(X, R) - Q(X, L) - (R-L)*S;
			long double idx = difff/x;
			///printf("%Lf diffs\n", idx);
			ans.push_back(R-(int)round(idx));
			return;
		}
	}
	if (L+1 == R){
		ans.push_back(L+1);
		return;
	}
	ll mid = (L+R)/2;
	ld Q = getdiff(X, mid);
	dnc(L, mid, S, Q);
	dnc(mid, R, Q, E);
	
}
void solve(int subtask_id, int N) {
    ///printf("subtask_id = %d, N = %d\n", subtask_id, N);
    ll L = -10000*X - 10000 - 1;
    ll R = 10000*X + 10000 + 1;
    for (ll i = 0; i <= 10000; i++){
		long double D = (ld)(2.0)/sqrtl(i*i + 1);
		///printf("%.20Lf\n",D);
		diffs.push_back(D);
	}
    long double Q1 = getdiff(X, L);
    long double Q2 = getdiff(X, R);
    dnc(L, R, Q1, Q2);
    vector<int> a,b;
    for (auto x : ans){
		///printf("%lld\n",x);
		int A = round((ld)x/X);
		int B = x - A*X;
		a.push_back(A); b.push_back(B);
	}
    the_lines_are(a,b);
}
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