Submission #592170

#	Time	Username	Problem	Language	Result	Execution time	Memory
592170		tutis	Uplifting Excursion (BOI22_vault)	C++17	80 / 100	4986 ms	236792 KiB

vault

/*input
1 5
0 0 6

*/

#pragma GCC optimize ("O3")
#pragma GCC target("avx,avx2,fma")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
using namespace std;
using namespace __gnu_pbds;
template <typename T>
using oset = tree<T,  null_type,  less<T>,  rb_tree_tag,  tree_order_statistics_node_update>;

using ll = long long;
using ull = unsigned long long;
using ld = long double;
mt19937_64 rng(0);
int main()
{
	ios_base::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);
	ll M;
	ll L;
	cin >> M >> L;
	ll A_[2 * M + 1];
	ll* A = A_ + M;
	for (ll i = -M; i <= M; i++)
		cin >> A[i];
	L = -L;
	ll cnt = 0;
	for (ll l = -M; l <= M; l++)
	{
		L += l * A[l];
		cnt += A[l];
	}
	A[0] = 0;
	ld L_ = L;
	ld C_[2 * M + 1];
	ld* C = C_ + M;
	C[0] = 0;
	ll sum[M + 2];
	for (ll x = M; x >= 1; x--)
	{
		for (ll v : {x, -x})
		{
			C[v] = L_ / v;
			C[v] = max(ld(0), C[v]);
			C[v] = min(ld(A[v]), C[v]);
			L_ -= C[v] * v;
		}
		sum[x] = (ll)roundl(L_);
	}
	sum[0] = 0;
	sum[M + 1] = L;
	const ll mxdel = 50000;
	ll infi = 2e18;
	ll ej[M + 2][2 * mxdel + 1];
	for (ll a = 0; a <= M + 1; a++)
		for (ll b = 0; b <= 2 * mxdel; b++)
			ej[a][b] = infi;
	ej[M + 1][0 + mxdel] = 0;
	for (ll x = M; x >= 0; x--)
	{
		for (ll v : {x, -x})
		{
			for (ll a = -mxdel; a <= mxdel; a++)
			{
				ll val = sum[x + 1] + a - sum[x];
				ll e = ej[x + 1][a + mxdel];
				if (e == infi)
					continue;
				ll opt = 0;
				if (x != 0)
					opt = val / v;
				opt = max(opt, 0ll);
				opt = min(opt, A[v]);
				for (ll k = max(0ll, opt - x); k <= min(A[v], opt + x); k++)
				{
					ll val_ = val - k * v;
					ll e_ = e + k;
					if (abs(val_) <= mxdel)
					{
						if (e_ < ej[x][val_ + mxdel])
						{
							ej[x][val_ + mxdel] = e_;
						}
					}
				}
			}
		}
	}
	ll best = ej[0][mxdel];
	if (best != infi)
		cout << cnt - best << "\n";
	else
		cout << "impossible\n";
}

• Subtask 1: 5 / 5
• Subtask 2: 15 / 15
• Subtask 3-1: 10 / 10
• Subtask 3-2: 10 / 10
• Subtask 4-1: 10 / 10
• Subtask 4-2: 10 / 10
• Subtask 5-1: 10 / 10
• Subtask 5-2: 10 / 10
• Subtask 6-1: 0 / 10
• Subtask 6-2: 0 / 10