Submission #59043

#	Time	Username	Problem	Language	Result	Execution time	Memory
59043		choikiwon	Sandwich (JOI16_sandwich)	C++17	35 / 100	8007 ms	11644 KiB

sandwich

#include<bits/stdc++.h>
using namespace std;

typedef pair<int, int> pii;

const int MN = 402;

int E = 1;
int la[MN * MN * 4], nxt[MN * MN * 4], oppo[MN * MN * 4], deg[MN * MN * 2];
void add(int u, int v) {
    nxt[E] = la[u];
    la[u] = E;
    oppo[E] = v;
    deg[v]++;
    E++;
}

int N, M;
char G[MN][MN];

int f(int r, int c, int t) {
    return r * (2 * M) + c * 2 + t;
}

int ans[MN * MN * 2], vis[MN * MN * 2], pos = 1;
queue<int> q;

int main() {
    scanf("%d %d", &N, &M);

    for(int i = 0; i < N; i++) {
        scanf("\n");
        for(int j = 0; j < M; j++) {
            scanf("%c", &G[i][j]);
        }
    }

    for(int i = 0; i < N; i++) {
        for(int j = 0; j < M; j++) {
            for(int k = 0; k < 2; k++) {
                if(k) {
                    if(i) add(f(i - 1, j, k), f(i, j, k));
                }
                else if(i < N - 1) add(f(i + 1, j, k), f(i, j, k));
                if(k ^ (G[i][j] == 'N')) {
                    if(j) add(f(i, j - 1, G[i][j - 1] == 'Z'), f(i, j, k));
                }
                else if(j < M - 1) add(f(i, j + 1, G[i][j + 1] == 'N'), f(i, j, k));
            }
        }
    }

    for(int i = 0; i < N * M * 2; i++) if(!deg[i]) {
        q.push(i);
    }
    while(!q.empty()) {
        int u = q.front(); q.pop();

        for(int i = la[u]; i; i = nxt[i]) {
            int v = oppo[i];
            deg[v]--;
            if(!deg[v]) {
                q.push(v);
            }
        }
    }

    for(int i = 0; i < N; i++) {
        for(int j = 0; j < M; j++) {
            int k = G[i][j] == 'N';
            if(deg[ f(i, j, k) ]) continue;

            q.push(f(i, j, k));
            ans[ f(i, j, k) ] += M - j;
            vis[ f(i, j, k) ] = pos;
            while(!q.empty()) {
                int u = q.front(); q.pop();

                for(int x = la[u]; x; x = nxt[x]) {
                    int v = oppo[x];
                    if(!deg[v] && vis[v] != pos) {
                        q.push(v);
                        ans[v] += M - j;
                        vis[v] = pos;
                    }
                }
            }
        }
        pos++;
    }
    for(int i = 0; i < N; i++) {
        for(int j = M - 1; j >= 0; j--) {
            int k = G[i][j] == 'Z';
            if(deg[ f(i, j, k) ]) continue;

            q.push(f(i, j, k));
            ans[ f(i, j, k) ] += j + 1;
            vis[ f(i, j, k) ] = pos;
            while(!q.empty()) {
                int u = q.front(); q.pop();

                for(int x = la[u]; x; x = nxt[x]) {
                    int v = oppo[x];
                    if(!deg[v] && vis[v] != pos) {
                        q.push(v);
                        ans[v] += j + 1;
                        vis[v] = pos;
                    }
                }
            }
        }
        pos++;
    }

    for(int i = 0; i < N; i++) {
        for(int j = 0; j < M; j++) {
            if(deg[ f(i, j, 0) ] && deg[ f(i, j, 1) ]) printf("-1 ");
            else if(deg[ f(i, j, 0) ]) printf("%d ", 2 * ans[ f(i, j, 1) ]);
            else if(deg[ f(i, j, 1) ]) printf("%d ", 2 * ans[ f(i, j, 0) ]);
            else printf("%d ", 2 * min(ans[ f(i, j, 0) ], ans[ f(i, j, 1) ]));
        }
        printf("\n");
    }
}

Compilation message (stderr)

sandwich.cpp: In function 'int main()':
sandwich.cpp:29:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d %d", &N, &M);
     ~~~~~^~~~~~~~~~~~~~~~~
sandwich.cpp:32:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         scanf("\n");
         ~~~~~^~~~~~
sandwich.cpp:34:18: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
             scanf("%c", &G[i][j]);
             ~~~~~^~~~~~~~~~~~~~~~

• Subtask 1: 35 / 35
• Subtask 2: 0 / 65