Submission #58892

#TimeUsernameProblemLanguageResultExecution timeMemory
58892BenqSightseeing (NOI14_sightseeing)C++14
25 / 25
3329 ms258456 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/tree_policy.hpp> #include <ext/pb_ds/assoc_container.hpp> using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef long double ld; typedef complex<ld> cd; typedef pair<int, int> pi; typedef pair<ll,ll> pl; typedef pair<ld,ld> pd; typedef vector<int> vi; typedef vector<ld> vd; typedef vector<ll> vl; typedef vector<pi> vpi; typedef vector<pl> vpl; typedef vector<cd> vcd; template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; #define FOR(i, a, b) for (int i=a; i<(b); i++) #define F0R(i, a) for (int i=0; i<(a); i++) #define FORd(i,a,b) for (int i = (b)-1; i >= a; i--) #define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--) #define sz(x) (int)(x).size() #define mp make_pair #define pb push_back #define f first #define s second #define lb lower_bound #define ub upper_bound #define all(x) x.begin(), x.end() const int MOD = 1000000007; const ll INF = 1e18; const int MX = 500001; vector<array<int,3>> ed; int par[MX], ans[MX]; vi rpar[MX]; int V,E,Q; void unite(int c, int a, int b) { a = par[a], b = par[b]; if (a == b) return; if (par[1] == a) { for (int i: rpar[b]) ans[i] = c; } else if (par[1] == b) { for (int i: rpar[a]) ans[i] = c; } if (sz(rpar[a]) < sz(rpar[b])) swap(a,b); for (int i: rpar[b]) { par[i] = a; rpar[a].pb(i); } rpar[b].clear(); } int main() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> V >> E >> Q; FOR(i,1,V+1) { par[i] = i; rpar[i].pb(i); } F0R(i,E) { int a,b,c; cin >> a >> b >> c; ed.pb({c,a,b}); } sort(ed.rbegin(),ed.rend()); for (auto a: ed) unite(a[0],a[1],a[2]); F0R(i,Q) { int x; cin >> x; cout << ans[x] << "\n"; } } /* Look for: * the exact constraints (multiple sets are too slow for n=10^6 :( ) * special cases (n=1?) * overflow (ll vs int?) * array bounds */
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