Submission #587741

#	Time	Username	Problem	Language	Result	Execution time	Memory
587741		Koosha_mv	Meetings (IOI18_meetings)	C++14	0 / 100	42 ms	22048 KiB

meetings

#include "meetings.h"
#include <bits/stdc++.h>
using namespace std;
#define dbgv(v) cout<<#v<<" = "; f(i,0,int(v.size())) cout<<v[i]<<" "; cout<<endl
#define dbga(a,x,y) cout<<#a<<" = "; f(i,x,y) cout<<a[i]<<" "; cout<<endl
#define erorp(x) cout<<#x<<"={"<<x.F<<" , "<<x.S<<"}"<<endl
#define eror(x) cout<<#x<<'='<<(x)<<endl
#define f_(i,a,b) for(int i=a;i>=b;i--)
#define f(i,a,b) for(int i=a;i<b;i++)
#define nb(x) __builtin_popcount(x)
#define all(v) v.begin(),v.end()
#define bit(n,k) (((n)>>(k))&1)
#define Add(x,y) x=(x+y)%mod
#define maxm(a,b) a=max(a,b)
#define minm(a,b) a=min(a,b)
#define lst(x) x[x.size()-1]
#define sz(x) int(x.size())
#define mp make_pair
#define ll long long
#define pb push_back
#define S second
#define F first

const int N=1e6+99;
const ll inf=1e9+99;

int n,q;
ll res[N];
vector<ll> H,A;
vector<ll> ans;


struct node{
  int pfx,sfx,res,l,r;
  node(int x=-1){
    if(x==-1){
      pfx=sfx=res=l=r=0;
    }
    else{
      l=x,r=x+1;
      if(H[x]==1) pfx=sfx=res=1;
      else pfx=sfx=res=0;
    }
  }
  node friend operator + (node A,node B){
    node ans;
    ans.pfx=A.pfx;
    ans.sfx=B.sfx;
    ans.res=max(A.res,B.res);
    if(ans.pfx==A.r-A.l) ans.pfx+=B.pfx;
    if(ans.sfx==B.r-B.l) ans.sfx+=B.sfx;
    maxm(ans.res,A.sfx+B.pfx);
    return ans;
  }
} seg[N];

void build(int id=1,int l=0,int r=n){
  if(l+1==r){
    seg[id]=node(l);
    return ;
  }
  int mid=(l+r)>>1;
  build(id<<1,l,mid);
  build(id<<1|1,mid,r);
  seg[id]=seg[id<<1]+seg[id<<1|1];
}
node get(int L,int R,int id=1,int l=0,int r=n){
  if(r<=L || R<=l) return node();
  if(L<=l && r<=R){
    return seg[id];
  }
  int mid=(l+r)>>1;
  return get(L,R,id<<1,l,mid)+get(L,R,id<<1|1,mid,r);
}

vector<ll> minimum_costs(vector<int> _H,vector<int> L,vector<int> R){
  q=L.size(),n=_H.size();
  f(i,0,n) H.pb(_H[i]);
  ans.resize(q);
  build();
  f(i,0,q){
    int l=L[i],r=R[i]+1;
    ans[i]=2*(r-l)-get(l,r).res;
  }
  return ans;
}

• Subtask 1: 0 / 4
• Subtask 2: 0 / 15
• Subtask 3: 0 / 17
• Subtask 4: 0 / 24
• Subtask 5: 0 / 40