# | Submission time | Handle | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
584996 | 2022-06-28T08:21:52 Z | 반딧불(#8380) | JOI15_aaqqz (JOI15_aaqqz) | C++14 | 0 ms | 212 KB |
#include <bits/stdc++.h> using namespace std; typedef long long ll; const ll MOD1 = 1000000007; const ll MOD2 = 1000000009; int n, k; int arr[3002]; int frq[3002]; int ans; void calc1(){ for(int i=2; i<=n; i++){ int pnt = i; int maxVal = -1, maxCnt = 0; multiset<int> mst; while(pnt > 1){ pnt--; if(arr[i] < arr[pnt]){ maxVal = arr[pnt]; maxCnt = 1; break; } mst.insert(arr[pnt]); } if(maxVal==-1) continue; for(int j=i; j<=n; j++){ if(!mst.empty() && *mst.rbegin() > arr[j]) break; if(!mst.empty() && *mst.rbegin() == arr[j]){ ans = max(ans, 2*(j-i+1)+maxCnt); mst.erase(mst.find(arr[j])); continue; } bool good = 1; while(pnt > 1){ pnt--; if(arr[pnt] > arr[j]){ if(arr[pnt] == maxVal){ maxCnt++; continue; } good = 0; break; } mst.insert(arr[pnt]); if(arr[pnt] == arr[j]) break; } while(pnt > 1 && arr[pnt-1] == maxVal){ pnt++; maxCnt++; } if(!good || (mst.empty() || *mst.rbegin() < arr[j])) break; ans = max(ans, 2*(j-i+1)+maxCnt); mst.erase(mst.find(arr[j])); } } } void calc2(){ for(int i=1; i<n; i++){ int pnt = i; int minVal = 1e9, minCnt = 0; multiset<int> mst; while(pnt < n){ pnt++; if(arr[i] > arr[pnt]){ minVal = arr[pnt]; minCnt = 1; break; } mst.insert(arr[pnt]); } if(minVal==1e9) continue; for(int j=i; j>=1; j--){ if(!mst.empty() && *mst.begin() < arr[j]) break; if(!mst.empty() && *mst.begin() == arr[j]){ ans = max(ans, 2*(i-j+1)+minCnt); mst.erase(mst.find(arr[j])); continue; } bool good = 1; while(pnt < n){ pnt++; if(arr[pnt] < arr[j]){ if(arr[pnt] == minVal){ minCnt++; continue; } good = 0; break; } mst.insert(arr[pnt]); if(arr[pnt] == arr[j]) break; } while(pnt < n && arr[pnt+1] == minVal){ pnt++; minCnt++; } if(!good || (mst.empty() || *mst.begin() > arr[j])) break; ans = max(ans, 2*(i-j+1)+minCnt); mst.erase(mst.find(arr[j])); } } } int main(){ scanf("%d %d", &n, &k); for(int i=1; i<=n; i++) scanf("%d", &arr[i]), frq[arr[i]]++; ans = *max_element(frq+1, frq+k+1); for(int i=1; i<=n; i++){ for(int j=1; i-j>=1 && i+j<=n; j++){ if(arr[i-j] != arr[i+j]) break; ans = max(ans, j+j+1); } } for(int i=1; i<n; i++){ for(int j=0; i-j>=1 && i+j+1<=n; j++){ if(arr[i-j] != arr[i+j+1]) break; ans = max(ans, j+j+2); } } /// 1. - /// 2. - calc1(); calc2(); printf("%d", ans); }
Compilation message
# | Verdict | Execution time | Memory | Grader output |
---|---|---|---|---|
1 | Correct | 0 ms | 212 KB | Output is correct |
2 | Incorrect | 0 ms | 212 KB | Output isn't correct |
3 | Halted | 0 ms | 0 KB | - |
# | Verdict | Execution time | Memory | Grader output |
---|---|---|---|---|
1 | Correct | 0 ms | 212 KB | Output is correct |
2 | Incorrect | 0 ms | 212 KB | Output isn't correct |
3 | Halted | 0 ms | 0 KB | - |