Submission #58349

#	Time	Username	Problem	Language	Result	Execution time	Memory
58349		Benq	Ants (IZhO12_ants)	C++14	100 / 100	4 ms	708 KiB

ants

#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>

using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;

typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;

typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;

template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;

#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)

#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()

const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 100001;

int W,H,K,T;
vector<array<int,3>> hori[100], vert[100];
array<int,3> ans[100];

int main() {
    ios_base::sync_with_stdio(0); cin.tie(0);
    cin >> W >> H >> K >> T;
    F0R(i,K) {
        int X,Y,D; cin >> X >> Y >> D;
        if (D == 1) hori[Y].pb({X,1,i});
        else if (D == 3) hori[Y].pb({X,-1,i});
        else if (D == 2) vert[X].pb({Y,1,i});
        else vert[X].pb({Y,-1,i});
    }
    F0R(i,H) {
        int t = T%(2*W);
        vpi tmp;
        sort(all(hori[i]));
        for (auto& a: hori[i]) {
            if (a[1] == 1) {
                a[0] += t;
                if (a[0] >= W) {
                    a[0] = 2*W-a[0];
                    a[1] *= -1;
                }
                if (a[0] <= 0) {
                    a[0] = -a[0];
                    a[1] *= -1;
                }
            } else {
                a[0] -= t;
                if (a[0] <= 0) {
                    a[0] = -a[0];
                    a[1] *= -1;
                }
                if (a[0] >= W) {
                    a[0] = 2*W-a[0];
                    a[1] *= -1;
                }
            }
            tmp.pb({a[0],a[1]});
        }
        sort(all(tmp));
        F0R(j,sz(tmp)) ans[hori[i][j][2]] = {tmp[j].f,i,tmp[j].s == 1 ? 1 : 3};
    }
    F0R(j,W) {
        int t = T%(2*H);
        vpi tmp;
        sort(all(vert[j]));
        for (auto& a: vert[j]) {
            if (a[1] == 1) {
                a[0] += t;
                if (a[0] >= H) {
                    a[0] = 2*H-a[0];
                    a[1] *= -1;
                }
                if (a[0] <= 0) {
                    a[0] = -a[0];
                    a[1] *= -1;
                }
            } else {
                a[0] -= t;
                if (a[0] <= 0) {
                    a[0] = -a[0];
                    a[1] *= -1;
                }
                if (a[0] >= H) {
                    a[0] = 2*H-a[0];
                    a[1] *= -1;
                }
            }
            tmp.pb({a[0],a[1]});
        }
        sort(all(tmp));
        F0R(i,sz(tmp)) ans[vert[j][i][2]] = {j,tmp[i].f,tmp[i].s == 1 ? 2 : 4};
    }
    F0R(i,K) {
        F0R(j,3) cout << ans[i][j] << " ";
        cout << "\n";
    }
}

/* Look for:
* the exact constraints (multiple sets are too slow for n=10^6 :( ) 
* special cases (n=1?)
* overflow (ll vs int?)
* array bounds
*/

• Subtask 1: 100 / 100