Submission #58122

# Submission time Handle Problem Language Result Execution time Memory
58122 2018-07-16T21:55:09 Z Benq Mountain Trek Route (IZhO12_route) C++14
0 / 100
299 ms 66560 KB
#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>

using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;

typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;

typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;

template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;

#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)

#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()

const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 1000001;

int N;
int par[MX], L[MX], R[MX], h[MX];

int norm(int x) { return (x%N+N)%N; }

int get(int x) {
    if (par[x] != x) par[x] = get(par[x]);
    return par[x];
}

pi tri(int x) {
    x = get(norm(x));
    return {h[x],x};
}

void uniteLeft(int a, int b) {
    R[a] = R[b];
    par[b] = a;
}

void uniteRight(int a, int b) {
    L[a] = L[b];
    par[b] = a;
}

int mag(int a, int b) {
    if (b < a) b += N;
    return b-a+1;
}

ll k,ans,posi[MX];

int main() {
    ios_base::sync_with_stdio(0); cin.tie(0);
    cin >> N >> k;
    F0R(i,N) {
        cin >> h[i];
        L[i] = R[i] = par[i] = i;
    }
    vpi v; F0R(i,N) v.pb({h[i],i});
    sort(all(v));
    F0R(i,sz(v)-1) {
        auto a = v[i];
        // cout << a.f << " " << a.s << " " << L[a.s] << " " << R[a.s] << " " << mag(L[a.s],R[a.s]) << "\n";
        pi z1 = tri(L[a.s]-1);
        pi z2 = tri(R[a.s]+1);
        if (z1 < z2) {
            posi[mag(L[a.s],R[a.s])] += z1.f-a.f;
            uniteLeft(z1.s,a.s);
        } else {
            posi[mag(L[a.s],R[a.s])] += z2.f-a.f;
            uniteRight(z2.s,a.s);
        }
    }
    
    FOR(i,1,N) {
        int K = min(k/i,posi[i]);
        ans += K; k -= i*K;
    }
    cout << 2*ans;
}

/* Look for:
* the exact constraints (multiple sets are too slow for n=10^6 :( ) 
* special cases (n=1?)
* overflow (ll vs int?)
* array bounds
*/
# Verdict Execution time Memory Grader output
1 Correct 2 ms 376 KB Output is correct
2 Correct 3 ms 552 KB Output is correct
3 Correct 2 ms 552 KB Output is correct
4 Correct 2 ms 552 KB Output is correct
5 Correct 2 ms 552 KB Output is correct
6 Correct 2 ms 552 KB Output is correct
7 Correct 2 ms 552 KB Output is correct
8 Correct 3 ms 660 KB Output is correct
9 Correct 2 ms 704 KB Output is correct
10 Correct 28 ms 3780 KB Output is correct
11 Correct 49 ms 3780 KB Output is correct
12 Correct 41 ms 4732 KB Output is correct
13 Correct 258 ms 42788 KB Output is correct
14 Correct 254 ms 52188 KB Output is correct
15 Correct 299 ms 59856 KB Output is correct
16 Runtime error 231 ms 66560 KB Memory limit exceeded: We have a known bug that the memory usage is measured incorrectly (possibly because of Meltdown/Spectre patch), so your solution may be correct. Please submit again. Sorry for the inconvenience.
17 Halted 0 ms 0 KB -