Submission #58120

#	Time	Username	Problem	Language	Result	Execution time	Memory
58120		Benq	Mountain Trek Route (IZhO12_route)	C++14	0 / 100	4 ms	632 KiB

route

#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>

using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;

typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;

typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;

template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;

#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)

#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()

const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 1000001;

int N;
int par[MX], L[MX], R[MX], h[MX];

int norm(int x) { return (x%N+N)%N; }

int get(int x) {
    if (par[x] != x) par[x] = get(par[x]);
    return par[x];
}

pi tri(int x) {
    x = get(norm(x));
    return {h[x],x};
}

void uniteLeft(int a, int b) {
    R[a] = R[b];
    par[b] = a;
}

void uniteRight(int a, int b) {
    L[a] = L[b];
    par[b] = a;
}

int mag(int a, int b) {
    if (b < a) b += a;
    return b-a+1;
}

int k,ans,posi[MX];

int main() {
    ios_base::sync_with_stdio(0); cin.tie(0);
    cin >> N >> k;
    F0R(i,N) {
        cin >> h[i];
        L[i] = R[i] = par[i] = i;
    }
    vpi v; F0R(i,N) v.pb({h[i],i});
    sort(all(v));
    F0R(i,sz(v)-1) {
        auto a = v[i];
        pi z1 = tri(L[a.s]-1);
        pi z2 = tri(R[a.s]+1);
        if (z1 < z2) {
            posi[mag(L[a.s],R[a.s])] += z1.f-a.f;
            uniteLeft(z1.s,a.s);
        } else {
            posi[mag(L[a.s],R[a.s])] += z2.f-a.f;
            uniteRight(z2.s,a.s);
        }
    }
    
    FOR(i,1,N) {
        int K = min(k/i,posi[i]);
        ans += K; k -= i*K;
    }
    cout << 2*ans;
}

/* Look for:
* the exact constraints (multiple sets are too slow for n=10^6 :( ) 
* special cases (n=1?)
* overflow (ll vs int?)
* array bounds
*/

• Subtask 1: 0 / 100