Submission #58106

#TimeUsernameProblemLanguageResultExecution timeMemory
58106BenqBeautiful row (IZhO12_beauty)C++14
100 / 100
1204 ms165032 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/tree_policy.hpp> #include <ext/pb_ds/assoc_container.hpp> using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef long double ld; typedef complex<ld> cd; typedef pair<int, int> pi; typedef pair<ll,ll> pl; typedef pair<ld,ld> pd; typedef vector<int> vi; typedef vector<ld> vd; typedef vector<ll> vl; typedef vector<pi> vpi; typedef vector<pl> vpl; typedef vector<cd> vcd; template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; #define FOR(i, a, b) for (int i=a; i<(b); i++) #define F0R(i, a) for (int i=0; i<(a); i++) #define FORd(i,a,b) for (int i = (b)-1; i >= a; i--) #define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--) #define sz(x) (int)(x).size() #define mp make_pair #define pb push_back #define f first #define s second #define lb lower_bound #define ub upper_bound #define all(x) x.begin(), x.end() const int MOD = 1000000007; const ll INF = 1e18; const int MX = 100001; int N, num2[20], num3[20]; bool ok[20][20]; ll dp[1<<20][20]; int getOnes(int x, int y) { int ans = 0; while (x) { if (x % y == 1) ans ++; x /= y; } return ans; } int main() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> N; vi A(N); map<int,int> oc; F0R(i,N) { cin >> A[i]; oc[A[i]] ++; } F0R(i,N) { num2[i] = getOnes(A[i],2); num3[i] = getOnes(A[i],3); } F0R(i,N) F0R(j,N) if (num2[i] == num2[j] || num3[i] == num3[j]) ok[i][j] = 1; F0R(i,N) dp[1<<i][i] = 1; F0R(i,1<<N) F0R(j,N) if (i&(1<<j)) { F0R(k,N) if (!(i&(1<<k))) if (ok[j][k]) { dp[i^(1<<k)][k] += dp[i][j]; } } ll ans = 0; F0R(j,N) ans += dp[(1<<N)-1][j]; // for (auto a: oc) FOR(i,1,a.s+1) ans /= i; cout << ans; } /* Look for: * the exact constraints (multiple sets are too slow for n=10^6 :( ) * special cases (n=1?) * overflow (ll vs int?) * array bounds */
#Verdict Execution timeMemoryGrader output
Fetching results...