Submission #57987

#TimeUsernameProblemLanguageResultExecution timeMemory
57987BenqBob (COCI14_bob)C++14
120 / 120
205 ms64432 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/tree_policy.hpp> #include <ext/pb_ds/assoc_container.hpp> using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef long double ld; typedef complex<ld> cd; typedef pair<int, int> pi; typedef pair<ll,ll> pl; typedef pair<ld,ld> pd; typedef vector<int> vi; typedef vector<ld> vd; typedef vector<ll> vl; typedef vector<pi> vpi; typedef vector<pl> vpl; typedef vector<cd> vcd; template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; #define FOR(i, a, b) for (int i=a; i<(b); i++) #define F0R(i, a) for (int i=0; i<(a); i++) #define FORd(i,a,b) for (int i = (b)-1; i >= a; i--) #define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--) #define sz(x) (int)(x).size() #define mp make_pair #define pb push_back #define f first #define s second #define lb lower_bound #define ub upper_bound #define all(x) x.begin(), x.end() const int MOD = 1000000007; const ll INF = 1e18; const int MX = 100001; ll ans = 0; template<int SZ> struct DSU { int par[SZ], sz[SZ]; DSU() { F0R(i,SZ) par[i] = -1, sz[i] = 1; } int get(int x) { // path compression if (par[x] != x) par[x] = get(par[x]); return par[x]; } bool unite(int x, int y, int z) { // union-by-rank x = get(x), y = get(y); if (sz[x] < sz[y]) swap(x,y); ans += z*sz[x]*sz[y]; sz[x] += sz[y], par[y] = x; return 1; } }; int n,m,cur[1000]; int g[1000][1000]; vi nex[1001]; void solve(int x) { F0R(i,m+1) nex[i].clear(); F0R(i,n) nex[cur[i]-x].pb(i); DSU<1000> D = DSU<1000>(); F0Rd(i,m+1) for (int a: nex[i]) { // cout << a << "\n"; D.par[a] = a; ans += i; if (a > 0 && D.par[a-1] != -1 && g[a][x] == g[a-1][x]) D.unite(a,a-1,i); if (a < n-1 && D.par[a+1] != -1 && g[a][x] == g[a+1][x]) D.unite(a,a+1,i); } } int main() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> n >> m; F0R(i,n) F0R(j,m) cin >> g[i][j]; F0R(i,n) cur[i] = m; F0Rd(j,m) { if (j != m-1) F0R(i,n) if (g[i][j] != g[i][j+1]) cur[i] = j+1; solve(j); } cout << ans; } /* Look for: * the exact constraints (multiple sets are too slow for n=10^6 :( ) * special cases (n=1?) * overflow (ll vs int?) * array bounds */
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