Submission #578817

#	Time	Username	Problem	Language	Result	Execution time	Memory
578817		maomao90	Memory 2 (JOI16_memory2)	C++17	0 / 100	1 ms	212 KiB

memory2

// Hallelujah, praise the one who set me free
// Hallelujah, death has lost its grip on me
// You have broken every chain, There's salvation in your name
// Jesus Christ, my living hope
#include <bits/stdc++.h> 
#include "Memory2_lib.h"
using namespace std;

#define REP(i, s, e) for (int i = (s); i < (e); i++)
#define RREP(i, s, e) for (int i = (s); i >= (e); i--)
template <class T>
inline bool mnto(T& a, T b) {return a > b ? a = b, 1 : 0;}
template <class T>
inline bool mxto(T& a, T b) {return a < b ? a = b, 1: 0;}
typedef long long ll;
typedef long double ld;
#define FI first
#define SE second
typedef pair<int, int> ii;
typedef pair<ll, ll> pll;
typedef tuple<int, int, int> iii;
#define ALL(_a) _a.begin(), _a.end()
#define SZ(_a) (int) _a.size()
#define pb push_back
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<ii> vii;
typedef vector<iii> viii;

#ifndef DEBUG
#define cerr if (0) cerr
#endif

const int INF = 1000000005;
const ll LINF = 1000000000000000005ll;
const int MAXN = 105;

int n;
int a[MAXN];
vi ans[MAXN];

void Solve(int T, int N){
    n = N;
    int ptr = 0;
    memset(a, -1, sizeof a);
    while (ptr < 2 * n) {
        int bad = -1;
        REP (i, ptr + 1, 2 * n) {
            if (a[i] != -1) {
                continue;
            }
            a[i] = Flip(ptr, i);
            cerr << ptr << ' ' << i << ' ' << a[i] << '\n';
            ans[a[i]].pb(i);
            if (SZ(ans[a[i]]) >= 3) {
                bad = a[i];
                break;
            }
        }
        cerr << bad << '\n';
        if (bad != -1) {
            a[ptr] = bad;
            for (int i : ans[bad]) {
                a[i] = -1;
            }
            int nptr = ans[bad][0];
            ans[bad].clear();
            ans[bad].pb(ptr);
            ptr = nptr;
        } else {
            REP (i, 0, n) {
                if (SZ(ans[i]) == 1) {
                    a[ptr] = i;
                    ans[i].pb(ptr);
                    break;
                }
            }
            assert(a[ptr] != 0);
            break;
        }
    }
    REP (i, 0, n) {
        assert(SZ(ans[i]) == 2);
        Answer(ans[i][0], ans[i][1], i);
    }
}

• Subtask 1: 0 / 10
• Subtask 2: 0 / 50
• Subtask 3: 0 / 40