답안 #578315

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
578315 2022-06-16T11:08:02 Z johnf 순열 (APIO22_perm) C++17
71.2154 / 100
18 ms 1324 KB
#include "perm.h"
#include <bits/stdc++.h>

#define pb push_back
#define eb emplace_back
#define fi first
#define se second
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define for0(i, n) for (int i = 0; i < (int)(n); ++i)
#define for1(i, n) for (int i = 1; i <= (int)(n); ++i)
#define ford(i, n) for (int i = (int)(n)-1; i >= 0; --i)
#define fore(i, a, b) for (int i = (int)(a); i <= (int)(b); ++i)

using namespace std;

#ifdef LOCAL
#include "debug.h"
#else
#define debug(...) 42
#endif

using ll = long long;
using ld = long double;
using vi = vector<int>;

template <class T>
bool uin(T &a, T b) {
    return a > b ? (a = b, true) : false;
}
template <class T>
bool uax(T &a, T b) {
    return a < b ? (a = b, true) : false;
}

mt19937 rng(chrono::system_clock::now().time_since_epoch().count());

namespace sub1 {
bool eligible(ll k) { return k <= 90; }
vi construct_permutation(ll k) {
    vi ans;
    ford(i, k - 1) { ans.pb(i); }
    return ans;
}
}

namespace sub2 {
bool eligible(ll k) { return 1; }
vi construct_permutation(ll k) {
    k--;
    vi vec;
    for (int i = 62; i; i--) {
        while (k >= (1LL << i) - 1) {
            k -= (1LL << i) - 1;
            vec.pb(i);
        }
    }
    int n = accumulate(all(vec), 0);
    vi ans;
    for (auto d : vec) {
        fore(i, n - d, n - 1) { ans.pb(i); }
        n -= d;
    }
    return ans;
}
}

std::vector<int> construct_permutation(long long k) {
    if (sub1::eligible(k)) {
        return sub1::construct_permutation(k);
    }
    if (sub2::eligible(k)) {
        return sub2::construct_permutation(k);
    }
}

Compilation message

perm.cpp: In function 'std::vector<int> construct_permutation(long long int)':
perm.cpp:75:1: warning: control reaches end of non-void function [-Wreturn-type]
   75 | }
      | ^
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 1 ms 340 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 1 ms 340 KB Output is correct
3 Partially correct 1 ms 340 KB Partially correct
4 Partially correct 2 ms 340 KB Partially correct
5 Partially correct 5 ms 556 KB Partially correct
6 Partially correct 6 ms 596 KB Partially correct
7 Partially correct 7 ms 852 KB Partially correct
8 Partially correct 11 ms 1068 KB Partially correct
9 Correct 1 ms 340 KB Output is correct
10 Partially correct 18 ms 1324 KB Partially correct
11 Partially correct 10 ms 980 KB Partially correct
12 Partially correct 10 ms 964 KB Partially correct
13 Partially correct 9 ms 952 KB Partially correct