Submission #577241

#TimeUsernameProblemLanguageResultExecution timeMemory
577241dozerT-Covering (eJOI19_covering)C++14
100 / 100
318 ms70900 KiB
#include <bits/stdc++.h> using namespace std; #define sp " " #define endl "\n" #define fileio() freopen("input.txt", "r", stdin), freopen("output.txt", "w", stdout) #define fastio() cin.tie(0), ios_base::sync_with_stdio(0) #define pb push_back #define pii pair<int, int> #define st first #define nd second #define N 200005 #define L(node) node * 2 #define R(node) node * 2 + 1 #define int long long const int modulo = 1e9 + 7; int32_t main() { fastio(); pii dir[4] = {{1, 0}, {0, 1}, {-1, 0}, {0, -1}}; pii dia[4] = {{1, 1}, {-1, -1}, {-1, 1}, {1, -1}}; int n, m; cin>>n>>m; int arr[n + 5][m + 5], done[n + 5][m + 5]; vector<pii> adj[n + 5][m + 5]; memset(done , -1, sizeof(done)); for (int i = 1; i <= n; i++) { for (int j = 1; j <= m; j++) cin>>arr[i][j], done[i][j] = 0; } int k; cin>>k; set<pii> spe; int ans = 0; for (int i = 1; i <= k; i++) { int x, y; cin>>x>>y; spe.insert({x + 1, y + 1}); done[x + 1][y + 1] = 2; ans += arr[x + 1][y + 1]; } //handle the ones that have only one way of placement vector<pii> tmp(spe.begin(), spe.end()); for (auto i : tmp) { int x = i.st, y = i.nd; int cnt = 0, mini = modulo; for (int j = 0; j < 4; j++) { int a = dir[j].st, b = dir[j].nd; if (done[x + a][y + b] == 0) cnt++, mini = min(mini, arr[x + a][y + b]); } if (cnt < 3) { cout<<"No\n"; return 0; } if (cnt == 3) { for (int j = 0; j < 4; j++) { int a = dir[j].st, b = dir[j].nd; if (done[x + a][y + b] == 0) done[x + a][y + b] = 1, ans += arr[x + a][y + b]; } done[x][y] = 1; spe.erase(i); continue; } } //handle the diagonals, which have only one way of placement tmp = vector<pii> (spe.begin(), spe.end()); for (auto i : tmp) { int x = i.st, y = i.nd; if (done[x][y] == 1) continue; int cnt = 0, mini = modulo; pii ne; for (int j = 0; j < 4; j++) { int a = dia[j].st, b = dia[j].nd; if (done[x + a][y + b] == 2) cnt++, ne = {a, b}; } if (cnt > 1) { cout<<"No\n"; return 0; } if (cnt == 1) { int c = ne.st, d = ne.nd; done[x][y] = 1; done[x + c][y + d] = 1; spe.erase({x, y}); spe.erase({x + c, y + d}); cnt = 0; for (int j = 0; j < 4; j++) { int a = dir[j].st, b = dir[j].nd; if (done[x + a][y + b] == 0) cnt++, ans += arr[x + a][y + b], done[x + a][y + b] = 1; } if (done[x + 2 * c][y + d] == 0) cnt++, ans += arr[x + 2 * c][y + d], done[x + 2 * c][y + d] = 1; if (done[x + c][y + 2 * d] == 0) cnt++, ans += arr[x + c][y + 2 * d], done[x + c][y + 2 * d] = 1; if (cnt < 6) { cout<<"No\n"; return 0; } } } //handle the one that are left with one way of placement after placing the diagonals tmp = vector<pii> (spe.begin(), spe.end()); for (auto i : tmp) { int x = i.st, y = i.nd; int cnt = 0, mini = modulo; for (int j = 0; j < 4; j++) { int a = dir[j].st, b = dir[j].nd; if (done[x + a][y + b] == 0) cnt++, mini = min(mini, arr[x + a][y + b]); } if (cnt < 3) { cout<<"No\n"; return 0; } if (cnt == 3) { for (int j = 0; j < 4; j++) { int a = dir[j].st, b = dir[j].nd; if (done[x + a][y + b] == 0) done[x + a][y + b] = 1, ans += arr[x + a][y + b]; } done[x][y] = 1; spe.erase(i); continue; } } //todo: handle the components which have one square between each other tmp = vector<pii> (spe.begin(), spe.end()); for (auto i : tmp) { int x = i.st, y = i.nd; for (int j = 0; j < 2; j++) { int a = dir[j].st * 2, b = dir[j].nd * 2; if (x + a < 0 || y + b < 0) continue; if (done[x + a][y + b] == 2) adj[x][y].pb({x + a, y + b}), adj[x + a][y + b].pb({x, y}); } /* cout<<x<<sp<<y<<" : "<<endl; for (auto j : adj[x][y]) cout<<j.st<<sp<<j.nd<<endl; */ } for (auto i : tmp) { int c = i.st, d = i.nd; if (done[c][d] == 1) continue; queue<pii> q; q.push({c, d}); int mini = modulo, cnt = 0; long long tot = 0; int steps = 0; pii ne; while(!q.empty()) { int x = q.front().st, y = q.front().nd; done[x][y] = 1; tot = tot + 1; //cout<<x<<sp<<y<<endl; spe.erase({x, y}); q.pop(); for (int j = 0; j < 4; j++) { int a = dir[j].st, b = dir[j].nd; if (done[x + a][y + b] == 0) { if (arr[x + a][y + b] < mini) ne = {x + a, y + b}; cnt++, mini = min(mini, arr[x + a][y + b]); ans += arr[x + a][y + b]; done[x + a][y + b] = 1; } } for (int j = 0; j < adj[x][y].size(); j++) { int a = adj[x][y][j].st, b = adj[x][y][j].nd; if (done[a][b] != 1) q.push({a, b}), done[a][b] = 1; } } if (cnt < tot * 3) { //cout<<cnt<<sp<<tot<<endl; cout<<"No\n"; return 0; } if (cnt > tot * 3) { done[ne.st][ne.nd] = 0; ans -= arr[ne.st][ne.nd]; } } //todo: choose the minimum ones tmp = vector<pii> (spe.begin(), spe.end()); for (auto i : tmp) { int x = i.st, y = i.nd; int cnt = 0, mini = modulo; pii ne; for (int j = 0; j < 4; j++) { int a = dir[j].st, b = dir[j].nd; if (done[x + a][y + b] == 0) { if (mini > arr[x + a][y + b]) ne = {x + a, y + b}; cnt++, mini = min(mini, arr[x + a][y + b]), ans += arr[x + a][y + b], done[x + a][y + b] = 1; } } if (cnt < 3) { cout<<"No\n"; return 0; } done[x][y] = 1; spe.erase(i); if (cnt == 4) { done[ne.st][ne.nd] = 0; ans -= arr[ne.st][ne.nd]; } } cout<<ans<<endl; cerr<<"time taken : "<<(float)clock() / CLOCKS_PER_SEC<<" seconds\n"; }

Compilation message (stderr)

covering.cpp: In function 'int32_t main()':
covering.cpp:80:16: warning: unused variable 'mini' [-Wunused-variable]
   80 |   int cnt = 0, mini = modulo;
      |                ^~~~
covering.cpp:191:22: warning: comparison of integer expressions of different signedness: 'long long int' and 'std::vector<std::pair<long long int, long long int> >::size_type' {aka 'long unsigned int'} [-Wsign-compare]
  191 |    for (int j = 0; j < adj[x][y].size(); j++)
      |                    ~~^~~~~~~~~~~~~~~~~~
covering.cpp:169:7: warning: unused variable 'steps' [-Wunused-variable]
  169 |   int steps = 0;
      |       ^~~~~
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