Submission #574732

#TimeUsernameProblemLanguageResultExecution timeMemory
574732MohammadAghilPalindrome-Free Numbers (BOI13_numbers)C++14
72.50 / 100
1 ms348 KiB
#include <bits/stdc++.h> #pragma GCC optimize ("Ofast,unroll-loops") #pragma GCC target ("avx2") using namespace std; typedef long long ll; typedef pair<int, int> pp; #define er(args ...) cerr << __LINE__ << ": ", err(new istringstream(string(#args)), args), cerr << endl #define per(i,r,l) for(int i = (r); i >= (l); i--) #define rep(i,l,r) for(int i = (l); i < (r); i++) #define all(x) x.begin(), x.end() #define sz(x) (int)(x).size() #define pb push_back #define ss second #define ff first void err(istringstream *iss){}template<typename T,typename ...Args> void err(istringstream *iss,const T &_val, const Args&...args){string _name;*iss>>_name;if(_name.back()==',')_name.pop_back();cerr<<_name<<" = "<<_val<<", ",err(iss,args...);} mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); const ll mod = 1e9 + 7, maxn = 5e5+5, d = 11, lg = 18, inf = ll(1e9) + 5; ll pw(ll a,ll b,ll md=mod){if(!b)return 1;ll k=pw(a,b>>1ll);return k*k%md*(b&1ll?a:1)%md;} ll dp[lg][d][d]; ll f(ll a){ vector<int> dig; while(a) dig.pb(a%10), a /= 10; reverse(all(dig)); ll res = 0; rep(i,0,sz(dig)){ rep(k,0,dig[i]){ if((i && k == dig[i-1]) || (i > 1 && k == dig[i-2])) continue; res += dp[sz(dig)-i-1][(i?dig[i-1]:10)][k]; } if((i && dig[i] == dig[i-1]) || (i > 1 && dig[i] == dig[i-2])) break; } return res; } int main(){ cin.tie(0) -> sync_with_stdio(0); rep(i,0,d) rep(j,0,d) dp[0][i][j] = 1; rep(l,1,lg){ rep(i,0,d){ rep(j,0,d){ rep(k,0,d-1) if(k - i && k - j) dp[l][i][j] += dp[l-1][j][k]; } } } ll a, b; cin >> b >> a; cout << f(a+1) - f(b) << '\n'; return 0; }

Compilation message (stderr)

numbers.cpp: In function 'll f(ll)':
numbers.cpp:24:6: warning: this 'while' clause does not guard... [-Wmisleading-indentation]
   24 |      while(a) dig.pb(a%10), a /= 10; reverse(all(dig));
      |      ^~~~~
numbers.cpp:24:38: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'while'
   24 |      while(a) dig.pb(a%10), a /= 10; reverse(all(dig));
      |                                      ^~~~~~~
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...