This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <vector>
#include "communication.h"
typedef long long ll;
using namespace std;
struct interval {
ll l, r;
interval(ll l, ll r) : l(l), r(r) {}
bool contains(ll x) {
return l <= x && x < r;
}
ll length() {
return r - l;
}
interval shrink(ll o, ll s) {
return interval(min(r, l + o), min(r, l + o + s));
}
};
vector<interval> splitIntervals(vector<interval> c, ll o, ll s) {
vector<interval> r;
for (interval &it : c) {
if (s > 0 && it.length() - o > 0)
r.push_back(it.shrink(o, s));
s -= max(0LL, min(s, it.length() - o));
o -= min(o, it.length());
}
return r;
}
bool contains(vector<interval> c, ll x) {
for (interval &it : c)
if (it.contains(x))
return true;
return false;
}
struct state {
ll s[2] = {0, 0};
vector<vector<interval>> c;
state(ll N): c(2) {
s[1] = N;
c[1].emplace_back(1, N + 1);
}
state(vector<vector<vector<interval>>> &cs): c(2) {
for (int g = 0; g < 2; g++)
for (vector<interval> &c : cs[g])
add(g, c);
}
void add(int g, interval it) {
s[g] += it.length();
c[g].push_back(it);
}
void add(int g, vector<interval> &c) {
for (interval &it : c)
add(g, it);
}
vector<vector<vector<interval>>> split() {
vector<vector<vector<interval>>> r(2);
for (int g = 0; g < 2; g++) {
int s1 = (s[g] + g) / 2, s2 = s[g] - s1;
r[g].push_back(splitIntervals(c[g], 0, s1));
r[g].push_back(splitIntervals(c[g], s1, s2));
}
return r;
}
ll size() {
return s[0] + s[1];
}
vector<ll> remaining() {
vector<ll> r;
for (int g = 0; g < 2; g++)
for (interval &it : c[g])
for (ll v = it.l; v < it.r; v++)
r.push_back(v);
return r;
}
};
std::pair<int, int> solve(int N, int X = -1) {
state s(N);
while (s.size() > 3) {
vector<vector<vector<interval>>> c = s.split();
int b = X != -1 ? send(contains(c[0][0], X) || contains(c[1][0], X)) : receive();
c[0].erase(c[0].begin() + b);
swap(c[0][0], c[1][b]);
s = state(c);
}
vector<ll> r = s.remaining();
if ((int) r.size() == 3) {
int b1 = 1, b2;
for (int i = 0; i < 2 && b1; i++)
b1 = X != -1 ? send(r[0] == X || r[1] == X) : receive();
if (!b1)
b2 = X != -1 ? send(r[0] == X) : receive();
r.erase(r.begin() + (b1 ? 2 : (b2 ? 1 : 0)));
}
return {r[0], r.back()};
}
void encode(int N, int X) {
solve(N, X);
}
std::pair<int, int> decode(int N) {
return solve(N);
}
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