This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
// #pragma GCC optimize ("Ofast,unroll-loops")
// #pragma GCC target ("avx2")
using namespace std;
typedef long long ll;
typedef pair<long double, ll> pp;
#define er(args ...) cerr << __LINE__ << ": ", err(new istringstream(string(#args)), args), cerr << endl
#define per(i,r,l) for(int i = (r); i >= (l); i--)
#define rep(i,l,r) for(int i = (l); i < (r); i++)
#define all(x) x.begin(), x.end()
#define sz(x) (int)(x).size()
#define pb push_back
#define ss second
#define ff first
void err(istringstream *iss){}template<typename T,typename ...Args> void err(istringstream *iss,const T &_val, const Args&...args){string _name;*iss>>_name;if(_name.back()==',')_name.pop_back();cerr<<_name<<" = "<<_val<<", ",err(iss,args...);}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const ll mod = 998244353, maxn = 8e2 + 5, maxm = 1e5+5, lg = 10, inf = ll(1e9) + 5;
ll pw(ll a,ll b,ll md=mod){if(!b)return 1;ll k=pw(a,b>>1ll);return k*k%md*(b&1ll?a:1)%md;}
int m, r, c, u[maxn][maxn], a[maxm];
int cnt[16], dx[4] = {-1, 0, 1, 0}, dy[4] = {0, 1, 0, -1};
void slv1(){
pp ans = {inf, 0};
rep(i,0,r){
vector<int> lx(c), rx(c);
rep(j,0,c){
if(!u[i][j]) continue;
lx[j] = j;
if(j && u[i][j-1] && u[i][j-1] <= cnt[2]) lx[j] = lx[j-1];
}
per(j,c-1,0){
if(!u[i][j]) continue;
rx[j] = j;
if(j < c-1 && u[i][j+1] && u[i][j+1] <= cnt[8]) rx[j] = rx[j+1];
}
rep(j,0,c){
if(u[i][j]){
if(rx[j] - lx[j] + 1 < ans.ff) ans = {rx[j] - lx[j] + 1, 1};
else if(rx[j] - lx[j] + 1 == ans.ff) ans.ss++;
}
}
}
cout << ans.ff << '\n' << ans.ss << '\n';
}
// void slv2(){
// }
int main(){
cin.tie(0) -> sync_with_stdio(0);
string s; cin >> m >> r >> c >> s;
rep(i,0,m){
if(s[i] == 'E') a[i] = 1;
if(s[i] == 'S') a[i] = 2;
if(s[i] == 'W') a[i] = 3;
}
rep(i,0,r) rep(j,0,c) cin >> u[i][j];
rep(i,0,16){
vector<bool> is(4);
rep(j,0,4) if(i>>j&1) is[j] = true;
int f = -1;
rep(j,0,m) if(!is[a[j]]) f = j;
if(f == -1) cnt[i] = inf;
else{
int mx = 0, cr = 0;
int pos = f;
do{
if(is[a[f]]) cr++;
else mx = max(mx, cr), cr = 0;
f = (f + 1)%m;
}while(pos - f); mx = max(mx, cr);
cnt[i] = mx;
}
}
slv1();
// if(max(r, c) <= 50) slv2();
// else slv1();
return 0;
}
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