Submission #569602

#	Time	Username	Problem	Language	Result	Execution time	Memory
569602		OttoTheDino	Furniture (JOI20_furniture)	C++17	0 / 100	6 ms	356 KiB

furniture

#include <bits/stdc++.h>
using namespace std;

#define rep(i,s,e)                  for (int i = s; i <= e; ++i)
#define rrep(i,s,e)                 for (int i = s; i >= e; --i)
#define pb                          push_back
#define pf                          push_front
#define fi                          first
#define se                          second
#define all(a)                      a.begin(), a.end()
#define len(a)                      (int)a.size()
typedef long long ll;
typedef pair<int, int> ii;
typedef vector<ii> vii;
typedef vector<int> vi;
typedef vector<double> vd;
typedef vector<string> vs;
typedef vector<ll> vll;

int main() {
    ios::sync_with_stdio(0);
    cin.tie(0);

    int n, m; cin >> n >> m;
    int g[n+2][m+2] = {};
    rep (i,1,n) {
        rep (j,1,m) {
            cin >> g[i][j], g[i][j]^=1;
        }
    }

    rrep (i,n,1) {
        rrep (j,m,1) {
            bool b = 0;
            if (i<n) b |= g[i+1][j];
            if (j<m) b |= g[i][j+1];
            if (i==n && j==m) b = 1;
            g[i][j] &= b;
        }
    }


    int Q; cin >> Q;

    while (Q--) {

        int x, y; cin >> x >> y;

        int g2[n+2][m+2] = {};

        memcpy(g2, g, sizeof(g));

        queue<ii> q;
        q.push({x,y});
        while (len(q)) {
            int i = q.front().fi, j = q.front().se;
            q.pop();
            if ((i<x || j<y) && (!g2[i][j] || g2[i+1][j] || g2[i][j+1])) continue;
            g2[i][j] = 0;
            if (i>1 && g2[i-1][j]) q.push({i-1,j});
            if (j>1 && g2[i][j-1]) q.push({i,j-1});
        }

        if (!g2[1][1]) {
            cout << "0\n";
        }

        else {
            cout << "1\n";
            q.push({x,y});
            while (len(q)) {
                int i = q.front().fi, j = q.front().se;
                q.pop();
                if ((i<x || j<y) && (!g2[i][j] || g2[i+1][j] || g2[i][j+1])) continue;
                g[i][j] = 0;
                if (i>1 && g[i-1][j]) q.push({i-1,j});
                if (j>1 && g[i][j-1]) q.push({i,j-1});
            }
        }
    }
    return 0;
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 95