Submission #568721

#TimeUsernameProblemLanguageResultExecution timeMemory
568721maomao90Fish 2 (JOI22_fish2)C++17
13 / 100
4089 ms1740 KiB
// Hallelujah, praise the one who set me free // Hallelujah, death has lost its grip on me // You have broken every chain, There's salvation in your name // Jesus Christ, my living hope #include <bits/stdc++.h> using namespace std; template <class T> inline bool mnto(T& a, T b) {return a > b ? a = b, 1 : 0;} template <class T> inline bool mxto(T& a, T b) {return a < b ? a = b, 1: 0;} #define REP(i, s, e) for (int i = s; i < e; i++) #define RREP(i, s, e) for (int i = s; i >= e; i--) typedef long long ll; typedef long double ld; #define FI first #define SE second typedef pair<int, int> ii; typedef pair<ll, ll> pll; typedef tuple<int, int, int> iii; #define ALL(_a) _a.begin(), _a.end() #define SZ(_a) (int) _a.size() #define pb push_back typedef vector<int> vi; typedef vector<ll> vll; typedef vector<ii> vii; typedef vector<iii> viii; #ifndef DEBUG #define cerr if (0) cerr #endif const int INF = 1000000005; const ll LINF = 1000000000000000005ll; const int MAXN = 200005; int n; int a[MAXN]; int q; int ans; void solve(int l, int r, int big = 0) { ll sm = 0; ii mx = {-1, -1}; REP (i, l, r + 1) { sm += a[i]; mxto(mx, ii{a[i], i}); } if (sm < big) { return; } ans++; solve(l, mx.SE - 1, mx.FI); solve(mx.SE + 1, r, mx.FI); } int main() { #ifndef DEBUG ios::sync_with_stdio(0), cin.tie(0); #endif cin >> n; REP (i, 1, n + 1) { cin >> a[i]; } cin >> q; while (q--) { int t; cin >> t; if (t == 1) { int x, y; cin >> x >> y; a[x] = y; } else { int l, r; cin >> l >> r; ans = 0; solve(l, r); cout << ans << '\n'; } } return 0; }
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