Submission #56867

#	Time	Username	Problem	Language	Result	Execution time	Memory
56867		Benq	Bali Sculptures (APIO15_sculpture)	C++14	100 / 100	184 ms	1104 KiB

sculpture

#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>

using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;

typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;

typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;

template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;

#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)

#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()

const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 100001;

int N,A,B;
vi Y;
bitset<2001> posi[2001];

bool sat(ll sum, ll cur, int pos) {
    sum ^= (sum&cur);
    return sum<(1LL<<pos);
}


bool ok(ll cur, int pos) {
    if (A == 1) {
        int mn[2001]; mn[0] = 0;
        FOR(i,1,N+1) {
            mn[i] = MOD;
            ll sum = 0;
            F0Rd(j,i) {
                sum += Y[j];
                if (sat(sum,cur,pos)) mn[i] = min(mn[i],mn[j]+1);
            }
        }
        return mn[N] <= B;
    } else {
        posi[0][0] = 1;
        FOR(i,1,N+1) {
            posi[i].reset();
            ll sum = 0;
            F0Rd(j,i) {
                sum += Y[j];
                if (sat(sum,cur,pos)) posi[i] |= (posi[j]<<1);
            }
        }
        FOR(i,A,B+1) if (posi[N][i]) return 1;
        return 0;
    }
}

void solve() {
    ll cur = 0;
    F0Rd(i,45) if (!ok(cur,i)) cur ^= 1LL<<i;
    cout << cur;
}

int main() {
    ios_base::sync_with_stdio(0); cin.tie(0);
    cin >> N >> A >> B; Y.resize(N);
    F0R(i,N) cin >> Y[i];
    solve();
}

/* Look for:
* the exact constraints (multiple sets are too slow for n=10^6 :( ) 
* special cases (n=1?)
* overflow (ll vs int?)
* array bounds
*/

• Subtask 1: 9 / 9
• Subtask 2: 16 / 16
• Subtask 3: 21 / 21
• Subtask 4: 25 / 25
• Subtask 5: 29 / 29