Submission #567053

#	Time	Username	Problem	Language	Result	Execution time	Memory
567053		maomao90	Misspelling (JOI22_misspelling)	C++17	28 / 100	54 ms	11896 KiB

misspelling

// Hallelujah, praise the one who set me free
// Hallelujah, death has lost its grip on me
// You have broken every chain, There's salvation in your name
// Jesus Christ, my living hope
#include <bits/stdc++.h> 
using namespace std;

template <class T>
inline bool mnto(T& a, T b) {return a > b ? a = b, 1 : 0;}
template <class T>
inline bool mxto(T& a, T b) {return a < b ? a = b, 1: 0;}
#define REP(i, s, e) for (int i = s; i < e; i++)
#define RREP(i, s, e) for (int i = s; i >= e; i--)
typedef long long ll;
typedef long double ld;
#define FI first
#define SE second
typedef pair<int, int> ii;
typedef pair<ll, ll> pll;
typedef tuple<int, int, int> iii;
#define ALL(_a) _a.begin(), _a.end()
#define SZ(_a) (int) _a.size()
#define pb push_back
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<ii> vii;
typedef vector<iii> viii;

#ifndef DEBUG
#define cerr if (0) cerr
#endif

const int INF = 1000000005;
const ll LINF = 1000000000000000005ll;
const int MAXN = 205;
const int MOD = 1000000007;

int n, m;
int lr[MAXN][2];
ll dp[MAXN][MAXN][30];
ll ans;

int main() {
#ifndef DEBUG
    ios::sync_with_stdio(0), cin.tie(0);
#endif
    cin >> n >> m;
    REP (i, 0, m) {
        int a, b; cin >> a >> b;
        bool s = 0;
        if (a > b) {
            s = 1;
            swap(a, b);
        }
        mxto(lr[a][s], b);
    }
    REP (c, 0, 26) {
        dp[2][1][c] = 1;
    }
    REP (i, 2, n + 1) {
        int r[2] = {0, 0};
        RREP (j, i - 1, 1) {
            REP (z, 0, 2) {
                mxto(r[z], lr[j][z]);
            }
            REP (c, 0, 26) {
                // stay the same
                dp[i + 1][j][c] += dp[i][j][c]; 
                if (dp[i + 1][j][c] >= MOD) {
                    dp[i + 1][j][c] -= MOD;
                }
                REP (nc, 0, 26) {
                    if (c == nc) continue;
                    if (r[0] >= i && c < nc) {
                        continue;
                    }
                    if (r[1] >= i && c > nc) {
                        continue;
                    }
                    dp[i + 1][i][nc] += dp[i][j][c];
                    if (dp[i + 1][i][nc] >= MOD) {
                        dp[i + 1][i][nc] -= MOD;
                    }
                }
            }
        }
    }
    REP (j, 1, n + 1) {
        REP (c, 0, 26) {
            ans += dp[n + 1][j][c];
            if (ans >= MOD) {
                ans -= MOD;
            }
        }
    }
    cout << ans << '\n';
    return 0;
}

• Subtask 1: 8 / 8
• Subtask 2: 20 / 20
• Subtask 3: 0 / 29
• Subtask 4: 0 / 32
• Subtask 5: 0 / 11