This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include <bits/stdc++.h>
// iostream is too mainstream
#include <cstdio>
// bitch please
#include <iostream>
#include <algorithm>
#include <cstdlib>
#include <vector>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <list>
#include <cmath>
#include <iomanip>
#include <time.h>
#define dibs reserve
#define OVER9000 1234567890123456789LL
#define ALL_THE(CAKE,LIE) for(auto LIE =CAKE.begin(); LIE != CAKE.end(); LIE++)
#define tisic 47
#define soclose 1e-8
#define chocolate win
// so much chocolate
#define patkan 9
#define ff first
#define ss second
#define abs(x) ((x < 0)?-(x):x)
#define uint unsigned int
#define dbl long double
#define pi 3.14159265358979323846
using namespace std;
// mylittledoge
typedef long long cat;
#ifdef DONLINE_JUDGE
// palindromic tree is better than splay tree!
#define lld I64d
#endif
int cost_arr[2][1<<19];
int cost[1<<20];
int ans[1000000];
cat query[1000000];
int v[3*3*3*3*3*3*3*3];
void solve(int d, int B, int cl, int cr, int ql, int qr) {
if(ql == qr) return;
if(d == B-8) {
for(int i = 0; i < 3*3*3*3*3*3*3*3; i++) {
int x = i, y = 0, pw3 = 1;
for(int j = 0; j <= 8; j++) {
if(j == 8) {
v[i] = cost[cl+y];
break;
}
if(x%3 == 2) {
v[i] = v[i-pw3]+v[i-2*pw3];
break;
}
y += (1<<j) * (x%3);
x /= 3;
pw3 *= 3;
}
}
for(int i = ql; i < qr; i++) {
int w = 0;
for(int j = 7; j >= 0; j--) {
if((query[i]>>(20+d+j))&1) w = 3 * w + ((query[i]>>(d+j))&1);
else w = 3 * w + 2;
}
ans[(query[i]>>40)&((1LL<<20)-1)] += ((query[i]>>60) ? -v[w] : v[w]);
}
return;
}
if(d == B) {
for(int i = ql; i < qr; i++)
ans[(query[i]>>40)&((1LL<<20)-1)] += ((query[i]>>60) ? -cost[cl] : cost[cl]);
return;
}
int cnt[3] = {};
for(int i = ql; i < qr; i++) {
if((query[i]>>(20+d))&1) cnt[(query[i]>>(d))&1]++;
else cnt[2]++;
}
if(cnt[2] <= cnt[0] && cnt[2] <= cnt[1]) {
for(int i = 0; i < (1<<(B-1-d)); i++) {
cost_arr[0][i] = cost[cl+2*i];
cost_arr[1][i] = cost[cl+2*i+1];
}
for(int i = 0; i < (1<<(B-1-d)); i++) cost[cl+i] = cost_arr[0][i];
for(int i = 0; i < (1<<(B-1-d)); i++) cost[cl+(1<<(B-1-d))+i] = cost_arr[1][i];
int a = ql, b = ql+cnt[0]+cnt[2];
cat bits = (1LL<<(20+d)) + (1LL<<(d));
for(int i = ql; i < ql+cnt[0]+cnt[2]; i++) {
if((query[i]>>(20+d))&1) {
if((query[i]>>(d))&1) {
for(; b < qr && (query[b]&bits) == bits; b++) {}
if(b == qr) break;
swap(query[i], query[b]);
b++;
}
else {
while(a < i && ((query[a]>>(20+d))&1) == 1 && ((query[a]>>(d))&1) == 0) a++;
if(a == i) continue;
swap(query[i], query[a]);
a++;
}
}
}
solve(d+1, B, cl, cl+(1<<(B-1-d)), ql, ql+cnt[0]+cnt[2]);
a = ql;
for(int i = ql+cnt[0]; i < ql+cnt[0]+cnt[2]; i++) if(((query[i]>>(20+d))&1) == 1) {
for(; a < ql+cnt[0] && ((query[a]>>(20+d))&1) == 1; a++) {}
if(a == ql+cnt[0]) break;
swap(query[i], query[a]);
a++;
}
solve(d+1, B, cl+(1<<(B-1-d)), cr, qr-cnt[2]-cnt[1], qr);
return;
}
int x = (int) (cnt[1] < cnt[0]);
for(int i = 0; i < (1<<(B-1-d)); i++) {
cost_arr[0][i] = cost[cl+2*i+1-x];
cost_arr[1][i] = cost[cl+2*i] + cost[cl+2*i+1];
}
for(int i = 0; i < (1<<(B-1-d)); i++) cost[cl+i] = cost_arr[0][i];
for(int i = 0; i < (1<<(B-1-d)); i++) cost[cl+(1<<(B-1-d))+i] = cost_arr[1][i];
int a = ql, b = ql+cnt[1-x]+cnt[x];
for(int i = ql; i < ql+cnt[1-x]+cnt[x]; i++) {
if((query[i]>>(20+d))&1) {
if(((query[i]>>(d))&1) != x) {
while(a < i && ((query[a]>>(20+d))&1) == 1 && ((query[a]>>(d))&1) != x) a++;
if(a == i) continue;
swap(query[i], query[a]);
a++;
}
}
else {
while(b < qr && ((query[b]>>(20+d))&1) == 0) b++;
swap(query[i], query[b]);
b++;
i--;
}
}
for(int i = ql+cnt[1-x]; i < ql+cnt[1-x]+cnt[x]; i++) query[i] ^= 1LL<<60;
solve(d+1, B, cl, cl+(1<<(B-1-d)), ql, ql+cnt[1-x]+cnt[x]);
a = ql+cnt[1-x];
cat bits = (1LL<<(20+d)) + (1LL<<(d));
cat expect = (1LL<<(20+d)) + x * (1LL<<(d));
for(int i = ql; i < ql+cnt[1-x]; i++) if((query[i]&bits) == expect) {
while(a < ql+cnt[1-x]+cnt[x] && (query[a]&bits) == expect) a++;
if(a == ql+cnt[1-x]+cnt[x]) break;
swap(query[i], query[a]);
a++;
}
for(int i = ql+cnt[1-x]; i < ql+cnt[1-x]+cnt[x]; i++) query[i] ^= 1LL<<60;
solve(d+1, B, cl+(1<<(B-1-d)), cr, qr-cnt[2]-cnt[x], qr);
}
int main() {
cin.sync_with_stdio(0);
cin.tie(0);
cout << fixed << setprecision(10);
int B, Q;
char buf[(1<<20) + 10];
scanf("%d %d %s", &B, &Q, buf);
for(int i = 0; i < (1<<B); i++) {
int b = 0;
for(int j = 0; j < B; j++) b = 2*b + ((i>>j)&1);
cost[b] = buf[i]-'0';
}
// query: mask, bits, id
char buf_small[30];
for(int i = 0; i < Q; i++) {
scanf("%s", buf_small);
query[i] = (1LL*i)<<40;
for(int j = 0; j < B; j++) {
if(buf_small[j] == '?') continue;
query[i] += 1LL<<(j+20);
if(buf_small[j] == '1') query[i] += 1LL<<(j+0);
}
}
memset(ans, 0, sizeof(ans));
solve(0, B, 0, 1<<B, 0, Q);
for(int i = 0; i < Q; i++) cout << ans[i] << "\n";
return 0;}
// look at my code
// my code is amazing
Compilation message (stderr)
snake_escaping.cpp: In function 'int main()':
snake_escaping.cpp:169:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
scanf("%d %d %s", &B, &Q, buf);
~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~
snake_escaping.cpp:178:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
scanf("%s", buf_small);
~~~~~^~~~~~~~~~~~~~~~~
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |