Submission #564681

#	Time	Username	Problem	Language	Result	Execution time	Memory
564681		maomao90	Wild Boar (JOI18_wild_boar)	C++17	62 / 100	18096 ms	884432 KiB

wild_boar

// Hallelujah, praise the one who set me free
// Hallelujah, death has lost its grip on me
// You have broken every chain, There's salvation in your name
// Jesus Christ, my living hope
#include <bits/stdc++.h> 
using namespace std;

template <class T>
inline bool mnto(T& a, T b) {return a > b ? a = b, 1 : 0;}
template <class T>
inline bool mxto(T& a, T b) {return a < b ? a = b, 1: 0;}
#define REP(i, s, e) for (int i = s; i < e; i++)
#define RREP(i, s, e) for (int i = s; i >= e; i--)
typedef long long ll;
typedef long double ld;
#define FI first
#define SE second
typedef pair<int, int> ii;
typedef pair<ll, ll> pll;
typedef tuple<int, int, int> iii;
typedef tuple<ll, ll, ll> tll;
#define ALL(_a) _a.begin(), _a.end()
#define pb push_back
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<ii> vii;
typedef vector<iii> viii;

#ifndef DEBUG
#define cerr if (0) cerr
#endif

const int INF = 1000000005;
const ll LINF = 1000000000000000005ll;
const int MAXN = 2005;
const int MAXL = 100005;
const int BAG = 5;

int n, m, t, l, e;
vi adj[MAXN * 3];
int w[MAXN * 3];
int x[MAXL];
ll rd[MAXN][MAXN][BAG];
int fi[MAXN][MAXN][BAG], se[MAXN][MAXN][BAG];
ll dp[MAXL][BAG];

int par[MAXN][2];
ll dist[MAXN * 3][MAXN * 3][2];
priority_queue<tll, vector<tll>, greater<tll>> pq;
void dijkstra(int s) {
    REP (i, 0, e) {
        dist[s][i][0] = dist[s][i][1] = LINF;
    }
    REP (i, 0, n + 1) {
        par[i][0] = par[i][1] = -1;
        if (s <= n) {
            fi[s][i][0] = se[s][i][0] = -1;
        }
    }
    dist[s][s][0] = w[s];
    pq.push(tll{w[s], s, 0});
    while (!pq.empty()) {
        auto [d, u, tp] = pq.top(); pq.pop();
        if (d != dist[s][u][tp]) continue;
        for (int v : adj[u]) {
            int cpar = par[u][tp];
            if (u <= n && v > n && (v ^ 1) == cpar) {
                continue;
            }
            if (u > n) {
                cpar = adj[u ^ 1][0];
            }
            ll nd = d + w[v];
            if (mnto(dist[s][v][0], nd)) {
                pq.push(tll{nd, v, 0});
                if (v <= n) {
                    if (s <= n) {
                        fi[s][v][0] = fi[s][cpar][0] == -1 ? u : fi[s][cpar][0];
                        se[s][v][0] = u;
                    }
                    par[v][0] = u;
                }
            } else if (mnto(dist[s][v][1], nd) && v <= n && par[v][0] != u) {
                pq.push(tll{nd, v, 1});
                par[v][1] = u;
            }
        }
    }
}

int main() {
#ifndef DEBUG
    ios::sync_with_stdio(0), cin.tie(0);
#endif
    cin >> n >> m >> t >> l;
    e = n + 1;
    if (e & 1) {
        e++;
    }
    REP (i, 0, m) {
        int a, b, c; cin >> a >> b >> c;
        w[e] = c;
        adj[a].pb(e);
        adj[e].pb(b);
        e++;
        w[e] = c;
        adj[b].pb(e);
        adj[e].pb(a);
        e++;
    }
    REP (i, 1, e) {
        dijkstra(i);
    }
    REP (i, 1, n + 1) {
        REP (j, 1, n + 1) {
            if (i == j) continue;
            REP (z, 0, BAG) {
                rd[i][j][z] = LINF;
            }
            rd[i][j][0] = dist[i][j][0];
            for (int u : adj[i]) {
                for (int v : adj[j]) {
                    v ^= 1;
                    REP (z, 1, 3) {
                        if ((z == 1 && u == fi[i][j][0]) ||
                                (z == 2 && v == se[i][j][0])) {
                            continue;
                        }
                        if (mnto(rd[i][j][z], dist[u][v][0])) {
                            fi[i][j][z] = u;
                            se[i][j][z] = v;
                        }
                    }
                }
            }
            if (rd[i][j][1] != LINF) {
                for (int u : adj[i]) {
                    for (int v : adj[j]) {
                        v ^= 1;
                        if (u == fi[i][j][0] || v == se[i][j][1]) continue;
                        if (mnto(rd[i][j][3], dist[u][v][0])) {
                            fi[i][j][3] = u;
                            se[i][j][3] = v;
                        }
                    }
                }
            }
            if (rd[i][j][2] != LINF) {
                for (int u : adj[i]) {
                    for (int v : adj[j]) {
                        v ^= 1;
                        if (u == fi[i][j][2] || v == se[i][j][0]) continue;
                        if (mnto(rd[i][j][4], dist[u][v][0])) {
                            fi[i][j][4] = u;
                            se[i][j][4] = v;
                        }
                    }
                }
            }
            REP (z, 0, BAG) {
                cerr << i << ' ' << j << ' ' << z << ": " << rd[i][j][z] << ' ' << fi[i][j][z] << ' ' << se[i][j][z] << '\n';
            }
        }
    }
    x[0] = -1;
    REP (i, 1, l + 1) {
        cin >> x[i];
    }
    while (t--) {
        int p, q; cin >> p >> q;
        x[p] = q;
        REP (j, 0, BAG) {
            dp[1][j] = 0;
        }
        REP (i, 2, l + 1) {
            int p = x[i - 2], u = x[i - 1], v = x[i];
            REP (j, 0, BAG) {
                dp[i][j] = LINF;
                REP (k, 0, BAG) {
                    if (p != -1 && (se[p][u][k] ^ 1) == fi[u][v][j]) continue;
                    mnto(dp[i][j], dp[i - 1][k] + rd[u][v][j]);
                }
                cerr << i << ' ' << j << ": " << dp[i][j] << '\n';
            }
        }
        ll ans = LINF;
        REP (j, 0, BAG) {
            mnto(ans, dp[l][j]);
        }
        if (ans >= LINF) {
            ans = -1;
        }
        cout << ans << '\n';
    }
    return 0;
}

• Subtask 1: 12 / 12
• Subtask 2: 35 / 35
• Subtask 3: 15 / 15
• Subtask 4: 0 / 38