제출 #558383

#제출 시각아이디문제언어결과실행 시간메모리
558383Koosha_mvThe short shank; Redemption (BOI21_prison)C++14
100 / 100
1471 ms89184 KiB
#include <bits/stdc++.h>
using namespace std;
#define dbgv(v) cout<<#v<<" = "; f(i,0,v.size()) cout<<v[i]<<" "; cout<<endl
#define dbga(a,x,y) cout<<#a<<" = "; f(i,x,y) cout<<a[i]<<" "; cout<<endl
#define erorp(x) cout<<#x<<"={"<<x.F<<" , "<<x.S<<"}"<<endl
#define eror(x) cout<<#x<<'='<<(x)<<endl
#define f_(i,a,b) for(int i=a;i>=b;i--)
#define f(i,a,b) for(int i=a;i<b;i++)
#define nb(x) __builtin_popcount(x)
#define all(v) v.begin(),v.end()
#define bit(n,k) (((n)>>(k))&1)
#define Add(x,y) x=(x+y)%mod
#define maxm(a,b) a=max(a,b)
#define minm(a,b) a=min(a,b)
#define lst(x) x[x.size()-1]
#define sz(x) int(x.size())
#define mp make_pair
#define ll long long
#define pb push_back
#define S second
#define F first

const int N=4e6+99;

int n,d,t,ans,a[N],b[N],ps[N],L[N],R[N],ok[N];
int seg1[N<<2],seg2[N<<2],dp[N<<2];

void add(int L,int R,int val,int id=1,int l=1,int r=n+1){
	if(r<=L || R<=l) return ;
	if(L<=l && r<=R){
		seg1[id]+=val;
		dp[id]=seg1[id]+max(dp[id<<1],dp[id<<1|1]);
		return ;
	}
	int mid=(l+r)>>1;
	add(L,R,val,id<<1,l,mid);
	add(L,R,val,id<<1|1,mid,r);
	dp[id]=seg1[id]+max(dp[id<<1],dp[id<<1|1]);
}
void build(int id=1,int l=1,int r=n+1){
	if(l+1==r){
		seg2[id]=(ok[l] ? L[l] : N);
		return ;
	}
	int mid=(l+r)>>1;
	build(id<<1,l,mid);
	build(id<<1|1,mid,r);
	seg2[id]=min(seg2[id<<1],seg2[id<<1|1]);
}
int get(int id=1,int l=1,int r=n+1){
	int mid=(l+r)>>1;
	if(l+1==r) return l;
	if(dp[id<<1]>=dp[id<<1|1]) return get(id<<1,l,mid);
	return get(id<<1|1,mid,r);
}
void prt(int x,int id=1,int l=1,int r=n+1){
	if(r<=x || x<seg2[id]) return ;
	if(l+1==r){
		seg2[id]=N;
		add(L[l],R[l],-1);
		return ;
	}
	int mid=(l+r)>>1;
	prt(x,id<<1,l,mid);
	prt(x,id<<1|1,mid,r);
	seg2[id]=min(seg2[id<<1],seg2[id<<1|1]);
}

int32_t main(){
	ios:: sync_with_stdio(0), cin.tie(0), cout.tie(0);
	vector<int> vec(1);
	b[0]=N;
	cin>>n>>d>>t; t++;
	minm(d,n-1);
	f(i,1,n+1) cin>>a[i];
	f(i,1,n+1){
		ok[i]=1;
		if(a[i]<t){
			L[i]=R[i]=i;
			b[i]=min(n,i+t-a[i]-1);
			while(b[vec.back()]<=b[i]) vec.pop_back();
			vec.pb(i);
			continue ;
		}
		ok[i]=1;
		while(b[vec.back()]<i) vec.pop_back();
		L[i]=vec.back()+1;
		R[i]=i+1;
		if(L[i]==1) ans++,ok[i]=0;
		else add(L[i],R[i],1);
		
	}
	build();
	f(i,0,d){
		ans+=dp[1];
		int x=get();
		prt(x);
	}
	cout<<n-ans;
}
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