This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "jumps.h"
#include <bits/stdc++.h>
using namespace std;
int n, p1[200005][20], p2[200005][20], p3[200005][20], p4[200005][20], X[200005];
vector<int> lst[200005];
stack<int> s;
void init(int N, std::vector<int> H) {
n = N;
for (int i = 0; i < N; ++i) X[i] = H[i];
memset(p1,-1,sizeof(p1));
memset(p2,-1,sizeof(p2));
memset(p3,-1,sizeof(p3));
memset(p4,-1,sizeof(p4));
for (int i = 0; i < N; ++i) {
while (!s.empty() && H[i] >= H[s.top()]) s.pop();
if (!s.empty()) p1[i][0] = p3[i][0] = s.top();
s.push(i);
}
while (!s.empty()) s.pop();
for (int i = N-1; i >= 0; --i) {
while (!s.empty() && H[i] >= H[s.top()]) s.pop();
if (!s.empty()) p2[i][0] = p4[i][0] = s.top();
s.push(i);
}
for (int i = 0; i < N; ++i) if (p1[i][0] == -1 || (p1[i][0] != -1 && p2[i][0] != -1 && H[p1[i][0]] < H[p2[i][0]])) swap(p1[i][0], p2[i][0]);
for (int k = 1; k < 20; ++k) for (int i = 0; i < N; ++i) {
if (p1[i][k-1] == -1) p1[i][k] = -1;
else p1[i][k] = p1[p1[i][k-1]][k-1];
if (p2[i][k-1] == -1) p2[i][k] = -1;
else p2[i][k] = p2[p2[i][k-1]][k-1];
if (p3[i][k-1] == -1) p3[i][k] = -1;
else p3[i][k] = p3[p3[i][k-1]][k-1];
if (p4[i][k-1] == -1) p4[i][k] = -1;
else p4[i][k] = p4[p4[i][k-1]][k-1];
}
}
int minimum_jumps(int A, int B, int C, int D) {
int x = C;
for (int k = 19; k >= 0; --k) if (p3[x][k] != -1 && p3[x][k] > B) x = p3[x][k];
x = p3[x][0];
if (x >= A && x <= B && p4[x][0] >= C && p4[x][0] <= D) return 1;
int y = B;
for (int k = 19; k >= 0; --k) if (p4[y][k] != -1 && p4[y][k] < C) y = p4[y][k];
y = p4[y][0];
if (y < C || y > D) return -1;
x = B;
for (int k = 19; k >= 0; --k) if (p3[x][k] != -1 && X[p3[x][k]] <= X[y] && p3[x][k] >= A) x = p3[x][k];
int ans = 0;
for (int k = 19; k >= 0; --k) if (p1[x][k] != -1 && X[p1[x][k]] <= X[y]) ans += (1<<k), x = p1[x][k];
for (int k = 19; k >= 0; --k) if (p2[x][k] != -1 && X[p2[x][k]] <= X[y]) ans += (1<<k), x = p2[x][k];
if (x != y) return -1;
else return ans;
}
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