This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
// still only subtask 2
#include "holiday.h"
#include <bits/stdc++.h>
using namespace std;
struct SegmentTree {
int n;
struct Value {
long long sum = 0;
int size = 0;
friend Value operator+(const Value& a, const Value& b) {
return { a.sum + b.sum, a.size + b.size };
}
};
vector<Value> tree;
int round_up(int n) {
while (n & (n-1))
n++;
return n;
}
SegmentTree(int n_) : n(round_up(n_)), tree(2*n) { }
void set(int i, const Value& value) {
i += n;
tree[i] = value;
for (i /= 2; i > 0; i /= 2)
tree[i] = tree[2*i] + tree[2*i+1];
}
long long descend(int budget) {
if (tree[1].size <= budget)
return tree[1].sum;
long long sum = 0;
for (int i = 1; i < n;)
if (tree[2*i].size > budget)
i = 2*i;
else {
sum += tree[2*i].sum;
budget -= tree[2*i].size;
i = 2*i+1;
}
return sum;
}
};
long long findMaxAttraction(int n, int start, int d, int attraction[]) {
vector<int> sorted(n), rank(n);
iota(sorted.begin(), sorted.end(), 0);
sort(sorted.begin(), sorted.end(), [&](int i, int j) {
return attraction[i] > attraction[j];
});
for (int i = 0; i < n; i++)
rank[sorted[i]] = i;
SegmentTree tree(n);
long long ans = 0;
for (int r = 0; r < min(n, d); r++) {
tree.set(rank[r], { attraction[r], 1 });
ans = max(ans, tree.descend(d - r));
}
return ans;
}
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