Submission #552052

#TimeUsernameProblemLanguageResultExecution timeMemory
552052RaresFelixMonster Game (JOI21_monster)C++17
88 / 100
136 ms1828 KiB
#include "monster.h" #include <bits/stdc++.h> using namespace std; namespace da { int query_count = 0; } namespace { map<pair<int, int>, bool> R; } // namespace bool cmp(int st, int dr) { if(R.count({st, dr})) return R[{st, dr}]; else { ++da::query_count; R[{dr, st}] = !(R[{st, dr}] = Query(st, dr)); return R[{st, dr}]; } } bool is_cand(int p, int n) { int nr = 0; for(int i = 0; i < n; ++i) if(i != p) nr += cmp(p, i); return nr == 1; } using vi = vector<int>; void mrg_srt(vi &O, vi &tmp, int st, int dr) { if(st == dr) return; int mij = (st + dr) >> 1; mrg_srt(O, tmp, st, mij); mrg_srt(O, tmp, mij + 1, dr); int p1 = st, p2 = mij + 1, pf = st; while(p1 <= mij && p2 <= dr) tmp[pf++] = cmp(O[p1], O[p2]) ? O[p2++] : O[p1++]; while(p1 <= mij) tmp[pf++] = O[p1++]; while(p2 <= dr) tmp[pf++] = O[p2++]; for(int i = st; i <= dr; ++i) O[i] = tmp[i]; } vector<int> Solve(int n) { vector<int> O(n), Tmp(n); for(int i = 0; i < n; ++i) O[i] = i; mrg_srt(O, Tmp, 0, n - 1); //printf("Sort Init: %d\n", da::query_count); vector<int> OC; for(int i = 0; i < 2; ++i) if(is_cand(O[i], n)) OC.push_back(O[i]); int lgp = 2; for(int i = 0; i < n - 2; ++i) { if(cmp(O[i], O[i + 2])) lgp = i + 2; else break; } for(int i = lgp; i >= max(lgp-2, 2); --i) if(is_cand(O[i], n)) OC.push_back(O[i]); int zero; if(OC.size() == 2) zero = cmp(OC[0], OC[1]) ? OC[0] : OC[1]; else zero = OC[0]; //printf("Det0: %d\n", da::query_count); vector<int> NewO; NewO.push_back(zero); for(int i = 0; i < n; ++i) if(O[i] != zero) NewO.push_back(O[i]); int start = 1; for(int i = 1; i < n; ++i) { if(cmp(NewO[start-1], NewO[i])) { // urmatorul reverse(NewO.data() + start, NewO.data() + i + 1); start = i + 1; } } vector<int> R(n); //printf("Fin: %d\n", da::query_count); // for(int i = 0; i < n; ++i) cerr << R[i] << " "; cerr << "\n"; //for(int i = 0; i < n; ++i) cerr << NewO[i] << " "; cerr << "\n"; for(int i = 0; i < n; ++i) R[NewO[i]] = i; return R; }
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