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Submission #551879

# Submission time Handle Problem Language Result Execution time Memory
551879 2022-04-21T19:15:59 Z LucaDantas Abduction 2 (JOI17_abduction2) C++17
13 / 100
 5000 ms 464 KB 
#include <bits/stdc++.h>
using namespace std;

constexpr int maxn = 50010, inf = 0x3f3f3f3f;

int A[maxn], B[maxn], R, C;

int find_first_A(int id, int val) { int i; for(i = id+1; A[i] < val; i++); return i; }
int find_first_B(int id, int val) { int i; for(i = id+1; B[i] < val; i++); return i; }

int find_last_A(int id, int val) { int i; for(i = id-1; A[i] < val; i--); return i; }
int find_last_B(int id, int val) { int i; for(i = id-1; B[i] < val; i--); return i; }

int find_first(int lim_id, int lim_val, bool k) { return k == 0 ? find_first_A(lim_id, lim_val) : find_first_B(lim_id, lim_val); }
int find_last(int lim_id, int lim_val, bool k) { return k == 0 ? find_last_A(lim_id, lim_val) : find_last_B(lim_id, lim_val); }

long long go(int r, int c, bool k) {
	int procurar = k == 0 ? r : c, eu = k == 0 ? c : r;
	int p1 = find_last(procurar, k == 0 ? B[eu] : A[eu], k), d1 = procurar - p1, v1 = k == 0 ? A[p1] : B[p1]; // ultimo cara vertical com indice menor que c e valor maior que A[r]
	int p2 = find_first(procurar, k == 0 ? B[eu] : A[eu], k), d2 = p2 - procurar, v2 = k == 0 ? A[p2] : B[p2]; // primeiro cara vertical com indice maior que c e valor maior que A[r]
	
	if(v1 > v2) // quero manter a invariante de que v1 < v2 pra ficar mais fácil de calcular as coisas
		swap(p1, p2), swap(d1, d2), swap(v1, v2);

	// printf("%d %d (%d %d | %d) (%d %d | %d)\n", r, c, p1, v1, d1, p2, v2, d2);

	// subtraio 1 dos infinitos porque eu defini eles como o primeiro ponto fora do grid (0 ou R+1/C+1), então a distância deles fica 1 a mais doq pode
	if(v1 == inf)
		return max(d1, d2)-1; // cheguei ao fim indo pra algum dos lados, escolho o maior obviamente
	if(v2 == inf)
		return max(d1 + (k == 0 ? go(p1, c, 1) : go(r, p1, 0)), (long long) d2-1); // cheguei ao fim indo pro maior mas não cheguei indo pro menor, então pego o melhor entre os dois

	int down = find_first(eu, v1, !k), dist_down = down - eu, v_down = k == 0 ? B[down] : A[down]; // primeiro cara abaixo de mim (row index > r) com valor > v1
	int up = find_last(eu, v1, !k), dist_up = eu - up, v_up = k == 0 ? B[up] : A[up];

	// printf("%d %d\n", up, down);

	// return 0;

	if(B[down] > B[up])
		swap(down, up), swap(dist_down, dist_up), swap(v_down, v_up);

	// brutao pq meu guloso ta dando errado
	return max((long long) d1 + (k == 0 ? go(p1, c, !k) : go(r, p1, !k)), (long long) d2 + (k == 0 ? go(p2, c, !k) : go(r, p2, !k)));

	/* if(B[down] < v2 || d1 >= d2) {
		// nesse caso ou o p1 tem algum vizinho melhor que o p2 ou eles tem os mesmo vizinhos mas se eu for pro p1 eu ando mais, entao vou pro p1
		return (long long) d1 + (k == 0 ? go(p1, c, !k) : go(r, p1, !k));
	}
	// nesse caso o p1 e o p2 tem os mesmo vizinhos mas o p2 é mais longe entao vou pra ele
	return (long long) d2 + (k == 0 ? go(p2, r, !k) : go(r, p2, !k)); */
}

int main() {
	int q; scanf("%d %d %d", &R, &C, &q);
	for(int i = 1; i <= R; i++)
		scanf("%d", &A[i]);
	for(int i = 1; i <= C; i++)
		scanf("%d", &B[i]);
	A[0] = A[R+1] = B[0] = B[C+1] = inf;
	while(q--) {
		int r, c; scanf("%d %d", &r, &c);
		// printf("%lld\n", go(r, c, 0));
		printf("%lld\n", max(go(r, c, 0), go(r, c, 1)));
	}
}

Compilation message

abduction2.cpp: In function 'int main()':
abduction2.cpp:55:14: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   55 |  int q; scanf("%d %d %d", &R, &C, &q);
      |         ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~
abduction2.cpp:57:8: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   57 |   scanf("%d", &A[i]);
      |   ~~~~~^~~~~~~~~~~~~
abduction2.cpp:59:8: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   59 |   scanf("%d", &B[i]);
      |   ~~~~~^~~~~~~~~~~~~
abduction2.cpp:62:18: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   62 |   int r, c; scanf("%d %d", &r, &c);
      |             ~~~~~^~~~~~~~~~~~~~~~~

Subtask #1
13.0 / 13.0

# Verdict Execution time Memory Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Correct 1 ms 212 KB Output is correct
4 Correct 0 ms 212 KB Output is correct
5 Correct 1 ms 212 KB Output is correct
6 Correct 0 ms 212 KB Output is correct
7 Correct 0 ms 212 KB Output is correct
8 Correct 1 ms 212 KB Output is correct
9 Correct 0 ms 212 KB Output is correct
10 Correct 0 ms 212 KB Output is correct
11 Correct 0 ms 312 KB Output is correct

Subtask #2
0 / 10.0

# Verdict Execution time Memory Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Correct 1 ms 212 KB Output is correct
4 Correct 0 ms 212 KB Output is correct
5 Correct 1 ms 212 KB Output is correct
6 Correct 0 ms 212 KB Output is correct
7 Correct 0 ms 212 KB Output is correct
8 Correct 1 ms 212 KB Output is correct
9 Correct 0 ms 212 KB Output is correct
10 Correct 0 ms 212 KB Output is correct
11 Correct 0 ms 312 KB Output is correct
12 Correct 1 ms 340 KB Output is correct
13 Correct 1 ms 340 KB Output is correct
14 Correct 1 ms 340 KB Output is correct
15 Correct 1 ms 324 KB Output is correct
16 Correct 1 ms 324 KB Output is correct
17 Correct 1 ms 320 KB Output is correct
18 Correct 2 ms 324 KB Output is correct
19 Execution timed out 5080 ms 356 KB Time limit exceeded
20 Halted 0 ms 0 KB -

Subtask #3
0 / 17.0

# Verdict Execution time Memory Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Correct 1 ms 212 KB Output is correct
4 Correct 0 ms 212 KB Output is correct
5 Correct 1 ms 212 KB Output is correct
6 Correct 0 ms 212 KB Output is correct
7 Correct 0 ms 212 KB Output is correct
8 Correct 1 ms 212 KB Output is correct
9 Correct 0 ms 212 KB Output is correct
10 Correct 0 ms 212 KB Output is correct
11 Correct 0 ms 312 KB Output is correct
12 Correct 1 ms 340 KB Output is correct
13 Correct 1 ms 340 KB Output is correct
14 Correct 1 ms 340 KB Output is correct
15 Correct 1 ms 324 KB Output is correct
16 Correct 1 ms 324 KB Output is correct
17 Correct 1 ms 320 KB Output is correct
18 Correct 2 ms 324 KB Output is correct
19 Execution timed out 5080 ms 356 KB Time limit exceeded
20 Halted 0 ms 0 KB -

Subtask #4
0 / 4.0

# Verdict Execution time Memory Grader output
1 Correct 154 ms 312 KB Output is correct
2 Correct 83 ms 324 KB Output is correct
3 Correct 129 ms 352 KB Output is correct
4 Correct 138 ms 340 KB Output is correct
5 Correct 192 ms 340 KB Output is correct
6 Correct 172 ms 464 KB Output is correct
7 Correct 157 ms 460 KB Output is correct
8 Execution timed out 5013 ms 356 KB Time limit exceeded
9 Halted 0 ms 0 KB -

Subtask #5
0 / 56.0

# Verdict Execution time Memory Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Correct 1 ms 212 KB Output is correct
4 Correct 0 ms 212 KB Output is correct
5 Correct 1 ms 212 KB Output is correct
6 Correct 0 ms 212 KB Output is correct
7 Correct 0 ms 212 KB Output is correct
8 Correct 1 ms 212 KB Output is correct
9 Correct 0 ms 212 KB Output is correct
10 Correct 0 ms 212 KB Output is correct
11 Correct 0 ms 312 KB Output is correct
12 Correct 1 ms 340 KB Output is correct
13 Correct 1 ms 340 KB Output is correct
14 Correct 1 ms 340 KB Output is correct
15 Correct 1 ms 324 KB Output is correct
16 Correct 1 ms 324 KB Output is correct
17 Correct 1 ms 320 KB Output is correct
18 Correct 2 ms 324 KB Output is correct
19 Execution timed out 5080 ms 356 KB Time limit exceeded
20 Halted 0 ms 0 KB -