This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include<bits/stdc++.h>
using namespace std;
int n, q;
struct node{
int lazy, mn, mx;
node(){
lazy=-1;
mn=0;
mx=0;
}
};
node tree[8000005];
int res[200005], num=0;
void propagate(int id, int l, int r){
if (l==r)return;
if (tree[id].lazy!=-1){
tree[id*2+1].lazy=tree[id].lazy;
tree[id*2+2].lazy=tree[id].lazy;
tree[id*2+1].mn=tree[id].lazy;
tree[id*2+1].mx=tree[id].lazy;
tree[id*2+2].mn=tree[id].lazy;
tree[id*2+2].mx=tree[id].lazy;
}
tree[id].mn=min(tree[id*2+1].mn, tree[id*2+2].mn);
tree[id].mx=max(tree[id*2+1].mx, tree[id*2+2].mx);
tree[id].lazy=-1;
}
void update1(int id, int l, int r, int L, int R, int h){
if (L>r || l>R || tree[id].mn>=h)return;
if (L<=l && r<=R && tree[id].mn==tree[id].mx){
tree[id].lazy=max(tree[id].lazy, h);
tree[id].mn=max(tree[id].mn, h);
tree[id].mx=max(tree[id].mx, h);
//cout<<id<<" "<<l<<" "<<r<<" "<<tree[id].lazy<<" "<<tree[id].mn<<" "<<tree[id].mx<<"\n";
return;
}
propagate(id, l, r);
int m=(l+r)/2;
update1(id*2+1, l, m, L, R, h);
update1(id*2+2, m+1, r, L, R, h);
tree[id].mn=min(tree[id*2+1].mn, tree[id*2+2].mn);
tree[id].mx=max(tree[id*2+1].mx, tree[id*2+2].mx);
}
void update2(int id, int l, int r, int L, int R, int h){
if (L>r || l>R || tree[id].mx<=h)return;
if (L<=l && r<=R && tree[id].mn==tree[id].mx){
if (tree[id].lazy!=-1)tree[id].lazy=min(tree[id].lazy, h);
else tree[id].lazy=h;
tree[id].mn=min(tree[id].mn, h);
tree[id].mx=min(tree[id].mx, h);
//cout<<id<<" "<<l<<" "<<r<<" "<<tree[id].lazy<<" "<<tree[id].mn<<" "<<tree[id].mx<<"\n";
return;
}
propagate(id, l, r);
int m=(l+r)/2;
update2(id*2+1, l, m, L, R, h);
update2(id*2+2, m+1, r, L, R, h);
tree[id].mn=min(tree[id*2+1].mn, tree[id*2+2].mn);
tree[id].mx=max(tree[id*2+1].mx, tree[id*2+2].mx);
}
void solve(int id, int l, int r){
propagate(id, l, r);
if (l==r){
res[num]=tree[id].mn;
num++;
return;
}
int m=(l+r)/2;
solve(id*2+1, l, m);
solve(id*2+2, m+1, r);
}
void buildWall(int n, int k, int op[], int left[], int right[], int height[], int finalHeight[]){
for (int i=0;i<k;i++){
if (op[i]==1)update1(0, 0, n-1, left[i], right[i], height[i]);
}
solve(0, 0, n-1);
for (int i=0;i<n;i++)finalHeight[i]=res[i];
return;
}
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