#include <bits/stdc++.h>
using namespace std;
struct seg{
seg *l, *r;
int a, b;
int minv, maxv;
};
seg* make(vector<int>&x, int a, int b){
seg* z = new seg();
z->a = a;
z->b = b;
if(a == b){
z->l = z->r = NULL;
z->minv = z->maxv = x[a];
} else {
z->l = make(x, a, (a+b)/2);
z->r = make(x, (a+b)/2+1, b);
z->minv = min(z->l->minv, z->r->minv);
z->maxv = max(z->l->maxv, z->r->maxv);
}
return z;
}
void kill(seg* r){
if(r == NULL) return;
kill(r->l);
kill(r->r);
delete r;
}
int idxatleast(seg* tree, int a, int b, int v){
if(tree->maxv < v || b < tree->a || tree->b < a) return -1;
if(tree->a == tree->b) return tree->a;
int idxr = idxatleast(tree->r, a, b, v);
if(idxr != -1) return idxr;
int idxl = idxatleast(tree->l, a, b, v);
if(idxl != -1) return idxl;
return -1;
}
int idxatmost(seg* tree, int a, int b, int v){
if(tree->minv > v || b < tree->a || tree->b < a) return -1;
if(tree->a == tree->b) return tree->a;
int idxr = idxatmost(tree->r, a, b, v);
if(idxr != -1) return idxr;
int idxl = idxatmost(tree->l, a, b, v);
if(idxl != -1) return idxl;
return -1;
}
// 0| 1| 2| 3| 4| 6|
// 23 1 1 3 4
vector<int> solve(int n, vector<int> &walls, vector<vector<int> > &keys){
// keys range from 0 to n
// rooms 0 ... n+1
// rooms
// 0 1 2 ... n n+1
// 0| 1| 2| n-1| n|
// walls
// for rooms 1 ... n, returns leftmost reachable room
vector<vector<int> > keylocations(n+1);
for(int i = 0; i <= n+1; i++){
for(int a : keys[i]){
keylocations[a].push_back(i);
}
}
vector<int> prevkey(n+1);
vector<int> nextkey(n+1);
for(int i = 0; i <= n; i++){
int type = walls[i];
auto it = lower_bound(keylocations[type].begin(), keylocations[type].end(), i+1);
nextkey[i] = *it;
prevkey[i] = *(it-1);
}
// for each wall, find farthest one so that there's a conflict
// then for a starting room, find dist to closest so that there is a conflict that extends past it
seg *p1 = make(prevkey, 0, prevkey.size()-1);
vector<int> conflict(n+1, -1);
for(int j = 0; j <= n; j++){
conflict[j] = idxatmost(p1, 0, nextkey[j]-1, j);
}
kill(p1);
seg *p2 = make(conflict, 0, conflict.size()-1);
vector<int> ans(n+2, -1);
for(int j = 1; j <= n; j++){
// ans[j] = j-1- max(k < j with c[k] >= j);
ans[j] = j - 1 - idxatleast(p2, 0, j-1, j);
}
kill(p2);
return ans;
}
int main(){
cin.sync_with_stdio(0); cin.tie(0);
int n;
cin >> n;
vector<int> walls; // what key need
walls.push_back(0);
for(int i = 1; i < n; i++){
int c;
cin >> c;
walls.push_back(c);
}
walls.push_back(0);
vector<vector<int> > keys(n+2);
for(int i = 0; i <= n; i++){
keys[0].push_back(i);
keys[n+1].push_back(i);
}
for(int i = 1; i <= n; i++){
int b;
cin >> b;
keys[i].resize(b);
for(int j = 0; j < b; j++){
cin >> keys[i][j];
}
}
int q;
cin >> q;
vector<int> x(q);
vector<int> y(q);
for(int i = 0; i < q; i++){
cin >> x[i] >> y[i];
}
vector<int> leftans = solve(n, walls, keys);
reverse(walls.begin(), walls.end());
reverse(keys.begin(), keys.end());
vector<int> rightans = solve(n, walls, keys);
reverse(rightans.begin(), rightans.end());
for(int i = 0; i < q; i++){
if(y[i]-x[i] <= rightans[x[i]] && y[i]-x[i] >= -leftans[x[i]]){
cout << "YES" << '\n';
} else {
cout << "NO" << '\n';
}
}
}
