# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
541945 | Olympia | Relativnost (COCI15_relativnost) | C++17 | 2071 ms | 24040 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <vector>
#include <algorithm>
#include <iostream>
#include <set>
#include <cmath>
#include <map>
#include <random>
#include <cassert>
#include <ctime>
#include <cstdlib>
#include <limits.h>
#include <queue>
using namespace std;
const int MOD = 10007;
class Node {
public:
int dp[21]; //how many ways such that exactly C people get a painting
bool id;
Node (bool id) {
this->id = id;
for (int i = 0; i < 21; i++) {
dp[i] = 0;
}
}
};
Node merge (Node n1, Node n2) {
if (!n1.id) return n2;
if (!n2.id) return n1;
Node ans(true);
for (int i = 0; i < 21; i++) {
for (int j = 0; j < 21; j++) {
ans.dp[min(i + j, 20)] += (n1.dp[j] * n2.dp[i]) % MOD;
}
}
for (int i = 0; i < 21; i++) {
ans.dp[i] %= MOD;
}
return ans;
}
Node get_node (pair<int,int> p) {
Node ans(true);
ans.dp[0] = p.second;
ans.dp[1] = p.first;
return ans;
}
template<class T>
class SegmentTree {
public:
SegmentTree (int N) {
N = (1 << ((int)floor(log2(N - 1)) + 1));
this->N = N;
val.assign(2 * N, Node(false));
}
void update (int x, T y) {
x += N - 1;
val[x] = y;
while (x != 0) {
x = (x - 1)/2;
val[x] = merge(val[2 * x + 1], val[2 * x + 2]);
}
}
vector<T> val;
private:
int N;
};
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int N, C;
cin >> N >> C;
SegmentTree<Node> st(N);
vector<int> x(N), y(N);
for (int i = 0; i < N; i++) cin >> x[i];
for (int i = 0; i < N; i++) cin >> y[i];
for (int i = 0; i < N; i++) {
x[i] %= MOD, y[i] %= MOD;
st.update(i, get_node({x[i], y[i]}));
}
int Q;
cin >> Q;
while (Q--) {
int ind, a, b;
cin >> ind >> a >> b;
a %= MOD, b %= MOD;
ind--;
st.update(ind, get_node({a, b}));
int64_t ans = 0;
for (int i = C; i <= 20; i++) {
ans += st.val[0].dp[i];
}
cout << ans % MOD << '\n';
}
}
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