Submission #541156

#TimeUsernameProblemLanguageResultExecution timeMemory
541156AlperenTMagneti (COCI21_magneti)C++17
110 / 110
201 ms118892 KiB
#include <bits/stdc++.h> using namespace std; const int N = 50 + 5, S = 1e4 + 5, MOD = 1e9 + 7; struct mint{ int val = 0; mint(long long a = 0) : val(a % MOD) {if(val < 0) val += MOD; } mint(long long a, long long b) {*this += a; *this /= b; } mint &operator += (const mint &b) {val += b.val; if(val >= MOD) val -= MOD; return *this; } mint &operator -= (const mint &b) {val -= b.val; if(val < 0) val += MOD; return *this; } mint &operator *= (const mint &b) {val = (1ll * val * b.val) % MOD; return *this; } mint mexp(mint a, long long b){ mint c(1); for(; b > 0; b /= 2, a *= a) if(b & 1) c *= a; return c; } mint minv(const mint &a) {return mexp(a, MOD - 2); }; mint &operator /= (const mint &b) {*this *= minv(b); return *this; } friend mint operator + (mint a, const mint &b) {return a += b; } friend mint operator - (mint a, const mint &b) {return a -= b; } friend mint operator - (const mint &a) {return 0 - a; } friend mint operator * (mint a, const mint &b) {return a *= b; } friend mint operator / (mint a, const mint &b) {return a /= b; } friend bool operator == (const mint &a, const mint &b) {return a.val == b.val; } friend bool operator != (const mint &a, const mint &b) {return a.val != b.val; } friend istream &operator >> (istream &is, mint &a) {long long b; is >> b; a = b; return is; } friend ostream &operator << (ostream &os, const mint &a) {return os << a.val; } }; int n, m, arr[N]; mint dp[N][N][S], fa[S], invfa[S], ans; void precalc(){ fa[0] = 1; for(int i = 1; i < S; i++) fa[i] = fa[i - 1] * i; invfa[S - 1] = mint().minv(fa[S - 1]); for(int i = S - 2; i >= 0; i--) invfa[i] = invfa[i + 1] * (i + 1); } mint calc(int stars, int bars){ return fa[bars + stars] * (invfa[bars] * invfa[stars]); } int main(){ ios_base::sync_with_stdio(false);cin.tie(NULL); precalc(); cin >> n >> m; for(int i = 1; i <= n; i++) cin >> arr[i]; sort(arr + 1, arr + n + 1); dp[0][0][0] = 1; for(int i = 0; i < n; i++){ for(int j = 0; j <= i; j++){ for(int k = 0; k <= m; k++){ if(k + 1 <= m) dp[i + 1][j + 1][k + 1] += dp[i][j][k]; if(k + arr[i + 1] <= m && j >= 1) dp[i + 1][j][k + arr[i + 1]] += dp[i][j][k] * j * 2; if(k + (arr[i + 1] * 2 - 1) <= m && j >= 2) dp[i + 1][j - 1][k + (arr[i + 1] * 2 - 1)] += dp[i][j][k] * j * (j - 1); } } } for(int i = 0; i <= m; i++) ans += dp[n][1][i] * calc(m - i, n); cout << ans; }
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