#include <bits/stdc++.h>
#include <ext/pb_ds/detail/standard_policies.hpp>
#include <ext/pb_ds/assoc_container.hpp> // Common file
#include <ext/pb_ds/tree_policy.hpp> // Including tree_order_statistics_node_update
#define f first
#define s second
#define pb push_back
#define mp make_pair
#define clr(dp,i) memset(dp,i,sizeof(dp))
#define opt ios_base::sync_with_stdio(NULL);cin.tie(NULL);cout.tie(NULL);
using namespace std;
using namespace __gnu_pbds;
typedef tree<int, null_type, less_equal<int>, rb_tree_tag,
tree_order_statistics_node_update> oset;
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
typedef pair<int, int> pii;
const long long mod = 1e9+7;
const ld pi = 3.14159265358979323846264338327950288;
//========================================
ll n, l, r, mx, sum[101], a[2001], dp[101][101], ans;
ll h = (1LL << 60) - 1;
bool sol(ll T)
{
clr(dp, 0);
dp[0][0] = 1;
for(int j=1; j<=r; j++)
{
for(int i=j; i<=n; i++)
{
ll tmp = 0;
for(int k=0; k<=i; k++)
{
ll enc = sum[i] - tmp;
enc ^= h;
//cout << sum[i] << " " << tmp << " " << b << " " << c << endl;
//cout << sum << " " << tmp << endl;
if(dp[k][j-1] && (enc & T) == T)
dp[i][j] = 1;
tmp += a[k];
}
}
}
for(int j=l; j<=r; j++)
{
if(dp[n][j])
return 1;
}
return 0;
}
int main()
{
opt;
cin >> n >> l >> r;
for(int i=0; i<n; i++)
cin >> a[i], sum[i+1] = sum[i] + a[i];
for(int i=60; i>=0; i--)
{
if(sol((ans | (1LL << i))))
ans |= (1LL << i);
}
cout << (ans^h) << endl;
}
