Submission #539883

#	Time	Username	Problem	Language	Result	Execution time	Memory
539883		browntoad	Dango Maker (JOI18_dango_maker)	C++14	100 / 100	537 ms	185872 KiB

dango_maker

#include <bits/stdc++.h>
#pragma GCC optimize ("Ofast", "unroll-loops")
using namespace std;
#define ll long long
#define int ll
#define FOR(i,a,b) for (int i = (a); i<(b); i++)
#define REP(i,n) FOR(i,0,n)
#define REP1(i,n) FOR(i,1,n+1)
#define RREP(i,n) for (int i=(n)-1; i>=0; i--)
#define RREP1(i,n) for (int i=(n); i>=1; i--)
#define f first
#define s second
#define pb push_back
#define ALL(x) x.begin(),x.end()
#define SZ(x) (int)(x.size())
#define SQ(x) (x)*(x)
#define pii pair<int, int>
#define pdd pair<double ,double>
#define pcc pair<char, char> 
#define endl '\n'
//#define TOAD
#ifdef TOAD
#define bug(x) cerr<<__LINE__<<": "<<#x<<" is "<<x<<endl
#define IOS()
#else
#define bug(...)
#define IOS() ios::sync_with_stdio(0), cin.tie(0), cout.tie(0)
#endif
 
const ll inf = 1ll<<60;
const int iinf=2147483647;
const ll mod = 1e9+7;
const ll maxn=3005;
const double PI=acos(-1);
 
ll pw(ll x, ll p, ll m=mod){
    ll ret=1;
    while (p>0){
        if (p&1){
            ret*=x;
            ret%=m;
        }
        x*=x;
        x%=m;
        p>>=1;
    }
    return ret;
}
 
ll inv(ll a, ll m=mod){
    return pw(a,m-2);
}
 
//=======================================================================================
char arr[maxn][maxn];
bool det(pii c, bool typ){
    if (typ) return (arr[c.f][c.s-1]=='R'&&arr[c.f][c.s]=='G'&&arr[c.f][c.s+1]=='W');
    else return (arr[c.f-1][c.s]=='R'&&arr[c.f][c.s]=='G'&&arr[c.f+1][c.s]=='W');
}
signed main (){
    IOS();
    int n, m; cin>>n>>m;
    vector<pii> run[n+m+1];
    REP1(i,n) REP1(j,m) {
        cin>>arr[i][j];
        run[i+j].pb({i, j});
    }
    int res=0;
    REP1(i, n+m){
        int dp0=0, dp1=0, dp2=0;
        REP(j,SZ(run[i])){
            int a=max({dp0, dp1, dp2});
            int b=(max(dp0, dp1)+1)*det(run[i][j], 0);
            int c=(max(dp0, dp2)+1)*det(run[i][j], 1);
            dp0=a; dp1=b; dp2=c;
        }
        res+=max({dp0, dp1, dp2});
    }
    cout<<res<<endl;
}   

• Subtask 1: 13 / 13
• Subtask 2: 20 / 20
• Subtask 3: 67 / 67