Submission #539187

#	Time	Username	Problem	Language	Result	Execution time	Memory
539187		akhan42	Hedgehog Daniyar and Algorithms (IZhO19_sortbooks)	C++17	64 / 100	3018 ms	205944 KiB

sortbooks

#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>

using namespace std;
using namespace __gnu_pbds;

#define F first
#define S second
#define forn(i, n) for(int i = 0; i < n; ++i)
#define forbn(i, b, n) for(int i = b; i < n; ++i)
#define sz(v) (int)v.size()
#define pb push_back
#define mp make_pair
#define eb emplace_back
#define all(v) v.begin(), v.end()
#define min3(a, b, c) min(a, min(b, c))
#define max3(a, b, c) max(a, max(b, c))

typedef pair<int, int> ii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef long long ll;
typedef complex<double> cd; // !!! long double slow

template <class T> inline void mineq(T &a, T b) { a = min(a, b); }
template <class T> inline void maxeq(T &a, T b) { a = max(a, b); }


int n, q;
const int INF = 1000 * 1000 * 1000 + 10;
const int MX = 2 * 1000 * 1000;
int ol[MX];


bool cmp(int v1, int v2) {
	return ol[v1] < ol[v2];
}


struct Seg {
	int mx[MX], t[MX];
	vi sl[MX];

	Seg(vi& a) {
		for(int p = n; p < 2 * n; p++) {
			mx[p] = a[p - n];
			sl[p].reserve(1);
			sl[p].pb(a[p - n]);
			t[p] = -INF;
			ol[p] = p - n;
		}

		for(int p = n - 1; p > 0; p--) {
			ol[p] = min(ol[2 * p], ol[2 * p + 1]);
			mx[p] = max(mx[2 * p], mx[2 * p + 1]);
			t[p] = max(t[2 * p], t[2 * p + 1]);
			sl[p].reserve(sz(sl[2 * p]) + sz(sl[2 * p + 1]));
			merge(all(sl[2 * p]), all(sl[2 * p + 1]), back_inserter(sl[p]));

			int ind = lower_bound(all(sl[2 * p + 1]), mx[2 * p]) - sl[2 * p + 1].begin();
			if(ind != 0)
				maxeq(t[p], mx[2 * p] + sl[2 * p + 1][ind - 1]);
		}
	}

	bool query(int l, int r, int k, int left_max) {
		vi vert;
		for (l += n, r += n + 1; l < r; l >>= 1, r >>= 1) {
			if (l & 1) {
				int v = l++;
				if(t[v] > k)
					return false;
				vert.pb(v);
			}
			if (r & 1) {
				int v = --r;
				if(t[v] > k)
					return false;
				vert.pb(v);
			}
		}
		sort(all(vert), cmp);

		for(int v: vert) {
			int ind = lower_bound(all(sl[v]), left_max) - sl[v].begin();
			if(ind != 0 && left_max + sl[v][ind - 1] > k)
				return false;

			maxeq(left_max, mx[v]);
		}

		return true;
	}
};



void solve() {
	cin >> n >> q;
	vi a(n);
	forn(i, n)
		cin >> a[i];

	Seg seg(a);

	forn(_, q) {
		int l, r, k;
		cin >> l >> r >> k;
		l--; r--;

		auto ans = seg.query(l, r, k, -INF);
		cout << ans << '\n';
	}
}


int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    cout.tie(nullptr);

//	freopen("boards.in", "r", stdin);
//	freopen("boards.out", "w", stdout);

    int t = 1;
//  cin >> t;
    while(t--) {
        solve();
    }
}

• Subtask 1: 8 / 8
• Subtask 2: 9 / 9
• Subtask 3: 0 / 13
• Subtask 4: 17 / 17
• Subtask 5: 30 / 30
• Subtask 6: 0 / 23