Submission #539144

#TimeUsernameProblemLanguageResultExecution timeMemory
539144akhan42Hedgehog Daniyar and Algorithms (IZhO19_sortbooks)C++17
64 / 100
2152 ms262144 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> using namespace std; using namespace __gnu_pbds; #define F first #define S second #define forn(i, n) for(int i = 0; i < n; ++i) #define forbn(i, b, n) for(int i = b; i < n; ++i) #define sz(v) (int)v.size() #define pb push_back #define mp make_pair #define eb emplace_back #define all(v) v.begin(), v.end() #define min3(a, b, c) min(a, min(b, c)) #define max3(a, b, c) max(a, max(b, c)) typedef pair<int, int> ii; typedef vector<int> vi; typedef vector<ii> vii; typedef long long ll; typedef complex<double> cd; // !!! long double slow template <class T> inline void mineq(T &a, T b) { a = min(a, b); } template <class T> inline void maxeq(T &a, T b) { a = max(a, b); } int n, q; const int INF = 1000 * 1000 * 1000 + 10; const int MX = 2 * 1000 * 1000; int ol[MX], oright[MX]; bool res[MX]; vi a; bool cmp(int v1, int v2) { return ol[v1] < ol[v2]; } struct Seg { int mx[MX], t[MX]; vi sl[MX]; vector<ii> rem[MX]; Seg(vi& a) { forn(i, MX) res[i] = true; for(int p = n; p < 2 * n; p++) { mx[p] = a[p - n]; sl[p].pb(a[p - n]); t[p] = -INF; oright[p] = ol[p] = p - n; } for(int p = n - 1; p > 0; p--) { ol[p] = min(ol[2 * p], ol[2 * p + 1]); oright[p] = max(oright[2 * p], oright[2 * p + 1]); mx[p] = max(mx[2 * p], mx[2 * p + 1]); t[p] = max(t[2 * p], t[2 * p + 1]); merge(all(sl[2 * p]), all(sl[2 * p + 1]), back_inserter(sl[p])); int ind = lower_bound(all(sl[2 * p + 1]), mx[2 * p]) - sl[2 * p + 1].begin(); if(ind != 0) maxeq(t[p], mx[2 * p] + sl[2 * p + 1][ind - 1]); } forn(i, MX) sl[i].clear(); } void query(int l, int r, int k, int left_max, int qid) { vi vert; for (l += n, r += n + 1; l < r; l >>= 1, r >>= 1) { if (l & 1) { vert.pb(l++); } if (r & 1) { vert.pb(--r); } } sort(all(vert), cmp); bool ans = true; for(int v: vert) { ans = ans && t[v] <= k; int rp = left_max - 1, lp = k - left_max + 1; if(lp <= rp) { rem[v].pb({lp - 1, qid}); rem[v].pb({rp, qid}); } maxeq(left_max, mx[v]); } res[qid] = ans; } void process() { for(int v = 1; v < 2 * n; v++) { sort(all(rem[v])); vi slv; for(int j = ol[v]; j <= oright[v]; j++) slv.pb(a[j]); sort(all(slv)); set<int> act; int i = 0; for(ii p: rem[v]) { int qid = p.S; if(res[qid] == false) continue; int en = p.F; if(i < sz(slv) && slv[i] <= en) { for(int qid_act: act) { res[qid_act] = false; } act.clear(); } while(i < sz(slv) && slv[i] <= en) i += 1; if(act.find(qid) == act.end()) { act.insert(qid); } else { act.erase(qid); } } rem[v].clear(); } } }; void solve() { cin >> n >> q; a.resize(n); forn(i, n) cin >> a[i]; Seg seg(a); int qq = q / 4; forn(qid, q) { int l, r, k; cin >> l >> r >> k; l--; r--; seg.query(l, r, k, -INF, qid); if(qid == qq || qid == 2 * qq || qid == 3 * qq) { seg.process(); } } seg.process(); forn(qid, q) { cout << res[qid] << '\n'; } } int main() { ios_base::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr); // freopen("boards.in", "r", stdin); // freopen("boards.out", "w", stdout); int t = 1; // cin >> t; while(t--) { solve(); } }
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