Submission #53855

#TimeUsernameProblemLanguageResultExecution timeMemory
53855SpeedOfMagicJob Scheduling (CEOI12_jobs)C++17
40 / 100
388 ms78000 KiB
/** MIT License Copyright (c) 2018 Vasilyev Daniil **/ #include <bits/stdc++.h> using namespace std; #pragma GCC optimize("Ofast") template<typename T> using v = vector<T>; //#define int long long typedef string str; typedef vector<int> vint; #define rep(a, l, r) for(int a = (l); a < (r); a++) #define pb push_back #define sz(a) ((int) a.size()) const long long inf = 4611686018427387903; //2^62 - 1 #if 0 //FileIO const string fileName = ""; ifstream fin ((fileName == "" ? "input.txt" : fileName + ".in" )); ofstream fout((fileName == "" ? "output.txt" : fileName + ".out")); #define get fin>> #define put fout<< #else #define get cin>> #define put cout<< #endif #define eol put endl void read() {} template<typename Arg,typename... Args> void read (Arg& arg,Args&... args){get (arg) ;read(args...) ;} void print(){} template<typename Arg,typename... Args> void print(Arg arg,Args... args){put (arg)<<" ";print(args...);} void debug(){eol;} template<typename Arg,typename... Args> void debug(Arg arg,Args... args){put (arg)<<" ";debug(args...);} int getInt(){int a; get a; return a;} //code goes here void run() { int n, d, m; read(n, d, m); n++; queue<int> a[n]; rep(i, 0, m) { int k; get k; a[k].push(i + 1); } int l = 0; int p = 1; int leftToFinish = 0; rep(r, 1, n + 1) { while (l + d < r) { p++; r--; int pointer = l; while (l <= r && pointer <= r) { while (l <= r && leftToFinish == 0) { l++; leftToFinish = sz(a[l]); } pointer = max(pointer, l); if (pointer > r) break; int z = min(r - pointer + 1, leftToFinish); leftToFinish -= z; pointer += z; } while (l <= r && leftToFinish == 0) { l++; leftToFinish = sz(a[l]); } r++; } if (r == n) break; int canDo = p; while (l <= r) { while (l <= r && leftToFinish == 0) { l++; leftToFinish = sz(a[l]); } if (canDo == 0 || l > r) break; int z = min(canDo, leftToFinish); canDo -= z; leftToFinish -= z; } } put p; eol; int ll = 1; rep(rr, 1, n) { int canDo = p; while(ll <= rr) { while (ll <= rr && a[ll].empty()) ll++; if (canDo == 0 || ll > rr) break; int z = min(canDo, sz(a[ll])); canDo -= z; while(z) { print(a[ll].front()); a[ll].pop(); z--; } } put 0; eol; } } int32_t main() {srand(time(0));ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);put setprecision(15);run();return 0;}
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