Submission #537144

#TimeUsernameProblemLanguageResultExecution timeMemory
537144BossBobsterRace (IOI11_race)C++17
0 / 100
3 ms4948 KiB
#include "race.h" #include <iostream> #include <string.h> #include <random> #include <fstream> #include <stdio.h> #include <stdlib.h> #include <time.h> #include <iomanip> #include <algorithm> #include <math.h> #include <cmath> #include <vector> #include <stack> #include <queue> #include <bitset> #include <map> #include <set> #include <unordered_map> #include <unordered_set> #include <complex> #include <valarray> using namespace std; //#include <ext/pb_ds/assoc_container.hpp> //#include <ext/pb_ds/tree_policy.hpp> //using namespace __gnu_pbds; //template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef pair<int, int> pii; typedef pair<int, string> pis; typedef pair<int, short> pish; typedef pair<string, string> pss; typedef pair<int, char> pic; typedef pair<pii, int> piii; typedef pair<double, double> pdd; typedef pair<float, float> pff; typedef long long ll; typedef long double ld; typedef unsigned long long ull; typedef unsigned int uint; typedef pair<ll, ll> pll; typedef pair<pll, ll> plll; typedef pair<pll, ld> plld; typedef pair<int, ll> pil; typedef pair<ull, ull> pull; typedef pair<ld, ld> pld; typedef complex<double> cd; //#define max(n, m) ((n>m)?n:m) //#define min(n, m) ((n<m)?n:m) #define f first #define s second #define input() ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0); #define eps 1e-9 //#define cin fin vector<pii> adj[200010]; int n, k, a, b, root; int sz[200010]; int p[200010]; bitset<200010> vis; int dfs1(int cur, int par) { sz[cur] = 1; for(auto nx : adj[cur]) if(nx.f != par && !vis[nx.f]) sz[cur] += dfs1(nx.f, cur); return sz[cur]; } int dfs2(int cur, int par, int n) { for(auto nx : adj[cur]) if(nx.f != par && sz[nx.f] > n/2 && !vis[nx.f]) return dfs2(nx.f, cur, n); return cur; } int mx; int ans = 2000000000; unordered_map<int, int> cnt; void dfs3(int cur, int par, int d, int num) { if(d > k) return; mx = max(mx, d); if(cnt[k-d]) ans = min(ans, num+cnt[k-d]); for(auto nx : adj[cur]) if(nx.f != par && !vis[nx.f]) dfs3(nx.f, cur, d+nx.s, num+1); } void dfs4(int cur, int par, int d, int num) { if(d > k) return; mx = max(mx, d); if(cnt[d] == 0) cnt[d] = 2000000000; cnt[d] = min(cnt[d], num); for(auto nx : adj[cur]) if(nx.f != par && !vis[nx.f]) dfs4(nx.f, cur, d+nx.s, num+1); } void make(int cur, int par) { int cent = dfs2(cur, par, dfs1(cur, par)); vis[cent] = 1; mx = 0; for(auto it : adj[cent]) if(!vis[it.f]) dfs3(it.f, cent, it.s, 1), dfs4(it.f, cent, it.s, 1); if(cnt[k]) ans = min(ans, cnt[k]); cnt.clear(); for(auto it : adj[cent]) if(!vis[it.f]) make(it.f, cent); } int best_path(int n2, int k2, int edges[][2], int nums[]) { for(int i = 0; i < n-1; i ++) adj[edges[i][0]].push_back({edges[i][1], nums[i]}), adj[edges[i][1]].push_back({edges[i][0], nums[i]}); k = k2; n = n2; make(0, -1); return ((ans==2000000000)?-1:ans); }
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