Submission #536716

#TimeUsernameProblemLanguageResultExecution timeMemory
536716kymSelf Study (JOI22_ho_t2)C++14
0 / 100
392 ms10908 KiB
#include <bits/stdc++.h> using namespace std; #define int ll #define FOR(i,s,e) for(ll i = s; i <= (ll)e; ++i) #define DEC(i,s,e) for(ll i = s; i >= (ll)e; --i) #define IAMSPEED ios_base::sync_with_stdio(false); cin.tie(0); #ifdef LOCAL #define db(x) cerr << #x << "=" << x << "\n" #define db2(x, y) cerr << #x << "=" << x << " , " << #y << "=" << y << "\n" #define db3(a,b,c) cerr<<#a<<"="<<a<<","<<#b<<"="<<b<<","<<#c<<"="<<c<<"\n" #define dbv(v) cerr << #v << ":"; for (auto ite : v) cerr << ite << ' '; cerr <<"\n" #define dbvp(v) cerr << #v << ":"; for (auto ite : v) cerr << "{" << ite.f << ',' << ite.s << "} "; cerr << "\n" #define dba(a,ss,ee) cerr << #a << ":"; FOR(ite,ss,ee) cerr << a[ite] << ' '; cerr << "\n" #define reach cerr << "LINE: " << __LINE__ << "\n"; #else #define db(x) #define db2(x,y) #define db3(a,b,c) #define dbv(v) #define dbvp(v) #define dba(a,ss,ee) #define reach #endif mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); #define ll long long #define pb push_back #define eb emplace_back #define all(x) (x).begin(), (x).end() #define f first #define s second #define g0(x) get<0>(x) #define g1(x) get<1>(x) #define g2(x) get<2>(x) #define g3(x) get<3>(x) typedef pair <ll, ll> pi; typedef tuple<ll,ll,ll> ti3; typedef tuple<ll,ll,ll,ll> ti4; ll rand(ll a, ll b) { return a + rng() % (b-a+1); } const int MOD = 1e9 + 7; const int inf = (int)1e9 + 500; const long long oo = (ll)1e18 + 500; template <typename T> void chmax(T& a, const T b) { a=max(a,b); } template <typename T> void chmin(T& a, const T b) { a=min(a,b); } const int MAXN = 300005; int n,m; int A[MAXN]; int B[MAXN]; bool check(int lim) { int extra = 0; FOR(i,1,n) { int num = (lim+A[i]-1)/A[i]; if(num<=m) { extra += m-num; } else { int lft=lim - A[i] * m; int need = (lft+B[i]-1)/B[i]; extra -= need; } } return extra >= 0; } int32_t main() { IAMSPEED cin >> n >> m; FOR(i,1,n) cin >> A[i]; FOR(i,1,n) cin >> B[i]; FOR(i,1,n) chmax(A[i], B[i]); int lo=-1,hi=10000000000000000ll; while(lo<hi-1) { int mid=(lo+hi)/2; if(check(mid))lo=mid; else hi=mid; } cout << lo; }
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